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def llIndex_Value (head, n): pass def llDelete_Last_item(head): pass

def llIndex_Value (head, n): pass def llDelete_Last_item(head): pass

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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I need help with the last two functions in python 

class ListNode: def __init__(self, data, next=None): self.data data self.next = next def __str__(self): temp = self result = [] while temp != None: result.append(str (temp.data)) temp temp.next result.append (str (None)) return "->".join(result) def llSize (head): number = self.head count = 0 while (number): count += 1 number = number.next return count def llIndex_Value (head, n): pass def llDelete_Last_item (head): pass def llReverse (head): first None currrent = self.head while (current is not None): next = current.next current.next = first first current current = next self.head = first return first
Transcribed Image Text:class ListNode: def __init__(self, data, next=None): self.data data self.next = next def __str__(self): temp = self result = [] while temp != None: result.append(str (temp.data)) temp temp.next result.append (str (None)) return "->".join(result) def llSize (head): number = self.head count = 0 while (number): count += 1 number = number.next return count def llIndex_Value (head, n): pass def llDelete_Last_item (head): pass def llReverse (head): first None currrent = self.head while (current is not None): next = current.next current.next = first first current current = next self.head = first return first
Instructions In basic.py you would be given 4 functions which are to find the size of the linked list, access a specific item using index value, delete the last item in the linked list and to reverse the linked list. Your task is to solve the functions and return their output. For the delete function, you are meant to return the last item which was deleted from the linked list. Constraints/Reminders • The linked list can be empty. In case where values can't be returned since it is empty return False. • Do not change the str function. Example Given a linked list_1->4->6->7 and an index of 3 • Your first function would return 4. • Your second would return 7. • Your third would return 7. • Your fourth would return 7->6->4->1 .
Transcribed Image Text:Instructions In basic.py you would be given 4 functions which are to find the size of the linked list, access a specific item using index value, delete the last item in the linked list and to reverse the linked list. Your task is to solve the functions and return their output. For the delete function, you are meant to return the last item which was deleted from the linked list. Constraints/Reminders • The linked list can be empty. In case where values can't be returned since it is empty return False. • Do not change the str function. Example Given a linked list_1->4->6->7 and an index of 3 • Your first function would return 4. • Your second would return 7. • Your third would return 7. • Your fourth would return 7->6->4->1 .
Expert Solution
Step 1c

 I have implemented the question in python as per the specification. I have also added a sample main function to run the provided test case and print the correct output. The code is as follows:

 

class ListNode:
def__init__(self,data,next=None)->None:
self.data=data
self.next=next
 
def__str__(self)->str:
temp=self
result=[]
whiletemp!=None:
result.append(str(temp.data))
temp=temp.next
result.append(str(None))
return"->".join(result)

defllSize(self):
temp=self
count=0
whiletemp!=None:
count+=1
temp=temp.next
returncount
 
defllIndex_Value(self,n):
temp=self
whiletemp!=Noneandn>=0:
ifn==0:
returntemp.data
else:
n-=1
temp=temp.next
returnNone
 
defllDelete_Last_Item(self):
temp=self
prev=self
whiletemp.next!=None:
prev=temp
temp=temp.next
 
prev.next=None
returntemp.data

if __name__ == "__main__":
node7=ListNode(7)
node6=ListNode(6,node7)
node4=ListNode(4,node6)
node1=ListNode(1,node4)

print(node1)
print(node1.llSize())
print(node1.llIndex_Value(3))
print(node1.llDelete_Last_Item())
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