Which of the following values cannot be probabilities? 3/5, 5/3, -0.44, 1, 2, 0, 0.02, 1.2

Q: Use the following probabilities to answer the question. It may be helpful to sketch a Venn diagram.…

A: Given information is shown in the even diagram

Q: Step 2 We are interested in the probabilities of finding r illiterate people, when r = 0, 1, 2, 3,…

A:

Q: Which of the following values cannot be probabilities? 3/5, 5/3, 0.08, 1, 0, 2, -0.42, 1.29 Select…

A: We know that the value of probability is lies between 0 and 1. Outside of this interval are not…

Q: Use the following probabilities to answer the question. It may be helpful to sketch a Venn diagram.…

A: Given Information P(A) = 0.73, P(B) = 0.22, P( A and B) = 0.05 P(not B and A) = P(A) - P(A and B) =…

Q: In a large population, 59% of the people have been vaccinated. If 5 people are randomly selected,…

A:

Q: Motor Vehicle Accidents During a recent year, there were 11.3 million automobile accidents, 5.4…

A: Number of automobile accidents = 11.3 million = 11,300,000 Number of truck accidents = 5.4 million =…

Q: Please solve the question attached

A: To find the expected profit, we need to use the expected value formula shown below.…

Q: Find the following probabilities. (a) P(negative | not pregnant) (b) P(not pregnant | positive)

A: Number of not pregnant = 58 Number of negative and Not pregnant = 55 Number of positive = 63 Number…

Q: Match the probability with the calculator command.

A: binompdf(n,p,x)=P(X=x) binomcdf(n,p,x)=P(X≤x)

Q: Which of the following values cannot be probabilities? 3/5, -0.5, √2, 0.09, 5/3, 0, 1, 1.23 Select…

A: probability define as The ratio of the number of favorable outcomes to certain event and total…

Q: P(A) = 0.61, P(B) = 0.67, P(BU A) = 0.91 Find the following probabilities. P(AN B) = P(B|A) = P(A|B)…

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Q: Which of the following could not possibly be probabilities?

A: Given values  A. -0.86 B. 1/2 C. 0 D. 0.78 The probability range is lies between 0 to 1  The…

Q: Which of the following values cannot be probabilities? 1,- 0.58, 1.23 √ 2, 0.02, 0, 5/3, 3/5

A: Answer:- We know that, The probability of the occurrence of an event lies between 0 and 1 . That is…

Q: Suppose P(A) = 0.2, P(B) - 0.45, and P(A n B) = 0.02. Find the following probabilities. P(A n B) =…

A: Given that, P(A) =0.2P(B) = 0.45P(A∩B)=0.02

Q: In a large population, 61% of the people have been vaccinated. If 5 people are randomly selected,…

A: From the given information, Sample size (n) = 5, Probability of success (p) = 0.61.

Q: Use the following probabilities to answer the question. Round to 4 decimal places.…

A: The given probabilities are P(A)=0.66 , P(B)=0.29 and P(A and B)=0.05

Q: Use the following probabilities to answer the question. Round to 4 decimal places. P(A) = 0.75, P(B)…

A: Given: P(A) = 0.75, P(B) = 0.2, P(A and B) = 0.05.

Q: Which of the following values cannot be probabilities? 1.00009 O 0.05 1.0 -0.0001 0.999

A: Solution-: Option (1) 1.00009 and (5) -0.0001

Q: Use the following probabilities to answer the question. Round to 4 decimal places.…

A: Solution: Given information:  P(A) =0.33 P(B)=0.62 P(A∩B)=0.05

Q: Use the following probabilities to answer the question. Round to 4 decimal places. P(A) = 0.21, P(B)…

A: P(A) = 0.21 P(B) = 0.74 P(A and B) = 0.05 P(B|A) = ?

Q: Suppose P(A) = 0.15, P(B) = 0.2, and P(A n B) = 0.06. Find the following probabilities. P(A n B) =…

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Q: None

A: In probability theory, probabilities must fall within the range of 0 to 1, inclusive. Therefore,…

Q: 0482 Start A game-show spinner has these odds of stopping on particular dollar values: 60% for $10,…

A: Solution: Given that,

Q: Use the following probabilities to answer the question. Round to 4 decimal places.…

A: P(A) = 0.72 P(B) = 0.18 P(A and B) = 0.10 We have, P(A and B) = P(B and A) To find conditional…

Q: The Addition Rule for the probability that events A or B or C will occur, P(A or B or C), is given…

A: Given that P(A)=0.35, P(B) = 0.22, P(C)=0.18 P(A and B) 0.11, P(A and C)=0.03, P(B and C)=0.08 , P(A…

Q: use the following probabilities to answer the question. Round to 4 decimal places.…

A: P(A) = 0.78P(B) = 0.17P(A and B) = 0.05

Q: Which of the following values cannot be probabilities? 1, 5/3, 0, - 0.46, 0.05, 3/5, 1.5, V2 Select…

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Q: Use the following probabilities to answer the question. Round to 4 decimal places. P(A) 0.44, P(B)…

A: It is given thatThe conditional probability of B given A can be calculated as follows.

Q: Which of the following values cannot be probabilities? 0.03, v2, 1, - 0.51, 0, 3/5, 5/3, 1.13 Select…

A:

Q: Which of the following values cannot be probabilities? 1, 2,5/3,-0.46, 0.03, 0, 1.53, 3/5 Select all…

A:

Q: Shown is the table indicating the marital status of the U.S. population in 2010. Numbers in the…

A: According to the problem, The number of divorced population, n=24 The number of divorced males, m=10…

Q: Use the following probabilities to answer the question. Round to 4 decimal places.…

A: Given, P(A)=0.54, P(B)=0.36, P(AandB)=0.10

Q: Use the following probabilities to answer the question. Round to 4 decimal places. P(A) = 0.61, P(B)…

A: It is given that P(A) = 0.61, P(B) = 0.29 P(A and B) = 0.10

Q: P(A)=0.57P(A)=0.57, P(B)=0.38P(B)=0.38 and P(AandB)=0.05P(AandB)=0.05. P(B∣A)=P(B∣A)=

A:

Continuous Probability Distributions

Probability distributions are of two types, which are continuous probability distributions and discrete probability distributions. A continuous probability distribution contains an infinite number of values. For example, if time is infinite: you could count from 0 to a trillion seconds, billion seconds, so on indefinitely. A discrete probability distribution consists of only a countable set of possible values.

Normal Distribution

Suppose we had to design a bathroom weighing scale, how would we decide what should be the range of the weighing machine? Would we take the highest recorded human weight in history and use that as the upper limit for our weighing scale? This may not be a great idea as the sensitivity of the scale would get reduced if the range is too large. At the same time, if we keep the upper limit too low, it may not be usable for a large percentage of the population!