Which of the following represents the first step in the mechanism of the Williamson ether synthesis, with correctly drawn curved arrows? Hi OH H-Na OH H-Na H-O

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Which of the following represents the first step in the mechanism of the Williamson ether synthesis, with correctly drawn curved arrows?

### Question 2

**Which of the following represents the first step in the mechanism of the Williamson ether synthesis, with correctly drawn curved arrows?**

The image presents a multiple-choice question featuring four option. The correct option must illustrate the first step in the Williamson ether synthesis mechanism, with properly drawn curved arrows to indicate the movement of electrons.

1. **(Choice A)**: 
   - The structure depicts an alcohol group (OH) bonded to a one-carbon chain.
   - There is a sodium hydride (H-Na) nearby.
   - Curved arrows indicate the movement of electrons from the alcohol oxygen to the hydrogen of the sodium hydride, and from the hydrogen to the sodium. 

2. **(Choice B)**:
   - Similar to Choice A, this structure depicts an alcohol group (OH) bonded to a one-carbon chain.
   - There is also a sodium hydride (H-Na) nearby.
   - Curved arrows are incorrectly drawn in this choice, displaying a different movement of electrons compared to Choice A.

3. **(Choice C)**:
   - The structure depicts an alkoxide ion (O-) bonded to a one-carbon chain.
   - A separate water molecule (HO-H) is represented with curved arrows indicating the incorrect mechanism steps.

4. **(Choice D)**:
   - This structure shows an alcohol group (OH) bonded to a two-carbon chain.
   - There is a separate water molecule (HO-H) nearby.
   - The curved arrows show an electron movement not consistent with the first step in the Williamson ether synthesis.

**Explanation of Diagram:**
- The detailed diagrams illustrate the molecules and the curved arrows indicating electron movement.
- Curved arrows are essential in organic chemistry to show the transfer of electron pairs during reactions.
- The correct mechanism involves the deprotonation of the alcohol (OH) by the base (sodium hydride, H-Na) to form the alkoxide ion and hydrogen gas.
  
From the presented options, **Choice A** correctly depicts the first step in the Williamson ether synthesis, where the alcohol oxygen donates electrons to the hydrogen of sodium hydride, forming an alkoxide ion.
Transcribed Image Text:### Question 2 **Which of the following represents the first step in the mechanism of the Williamson ether synthesis, with correctly drawn curved arrows?** The image presents a multiple-choice question featuring four option. The correct option must illustrate the first step in the Williamson ether synthesis mechanism, with properly drawn curved arrows to indicate the movement of electrons. 1. **(Choice A)**: - The structure depicts an alcohol group (OH) bonded to a one-carbon chain. - There is a sodium hydride (H-Na) nearby. - Curved arrows indicate the movement of electrons from the alcohol oxygen to the hydrogen of the sodium hydride, and from the hydrogen to the sodium. 2. **(Choice B)**: - Similar to Choice A, this structure depicts an alcohol group (OH) bonded to a one-carbon chain. - There is also a sodium hydride (H-Na) nearby. - Curved arrows are incorrectly drawn in this choice, displaying a different movement of electrons compared to Choice A. 3. **(Choice C)**: - The structure depicts an alkoxide ion (O-) bonded to a one-carbon chain. - A separate water molecule (HO-H) is represented with curved arrows indicating the incorrect mechanism steps. 4. **(Choice D)**: - This structure shows an alcohol group (OH) bonded to a two-carbon chain. - There is a separate water molecule (HO-H) nearby. - The curved arrows show an electron movement not consistent with the first step in the Williamson ether synthesis. **Explanation of Diagram:** - The detailed diagrams illustrate the molecules and the curved arrows indicating electron movement. - Curved arrows are essential in organic chemistry to show the transfer of electron pairs during reactions. - The correct mechanism involves the deprotonation of the alcohol (OH) by the base (sodium hydride, H-Na) to form the alkoxide ion and hydrogen gas. From the presented options, **Choice A** correctly depicts the first step in the Williamson ether synthesis, where the alcohol oxygen donates electrons to the hydrogen of sodium hydride, forming an alkoxide ion.
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