Reactions of Ethers
Ethers (R-O-R’) are compounds formed by replacing hydrogen atoms of an alcohol (R-OH compound) or a phenol (C6H5OH) by an aryl/ acyl group (functional group after removing single hydrogen from an aromatic ring). In this section, reaction, preparation and behavior of ethers are discussed in the context of organic chemistry.
Epoxides
Epoxides are a special class of cyclic ethers which are an important functional group in organic chemistry and generate reactive centers due to their unusual high reactivity. Due to their high reactivity, epoxides are considered to be toxic and mutagenic.
Williamson Ether Synthesis
An organic reaction in which an organohalide and a deprotonated alcohol forms ether is known as Williamson ether synthesis. Alexander Williamson developed the Williamson ether synthesis in 1850. The formation of ether in this synthesis is an SN2 reaction.
- Structure: A simple alkene with one double bond.
**B.** 
- Structure: Alkyne triple bond with nitro (NO₂) substituent.
**C.** 
- Structure: Contains a cycloalkene structure with additional substituents including an NO₂ group.
**D.** 
- Structure: Simple linear chain alkene.
**E.** 
- Structure: Cycloalkene with a chlorine (Cl) substituent.
### Ordering Task
____ ____ ____ ____ ____
Analyze the structures of these alkenes and rank their stability based on factors like hyperconjugation, steric hindrance, substituent effects, and resonance.
### Stability Considerations
- **Hyperconjugation:** More alkyl substituents on the double bond generally increase stability.
- **Steric Hindrance:** Less crowded alkenes are usually more stable.
- **Resonance:** Conjugation with electron-donating or withdrawing groups can affect stability.
- **Substituent Effects:** Groups like NO₂ (electron-withdrawing) and Cl can impact the electron density and stability.
By evaluating these factors, place each letter (A, B, C, D, E) in the spaces to indicate their relative stability, from lowest to highest.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F98834d82-84c5-4d71-9bf6-a3211e165794%2F1a4a9a93-b4ff-45fe-a90e-10b0faf4968a%2Fkjtz8na.jpeg&w=3840&q=75)
Trending now
This is a popular solution!
Step by step
Solved in 4 steps with 3 images
