Which of the following molecules cannot act as a nucleophile? (B) NH (C) BII, (D) PH, 10. Given that the pKa of acetone is 19, of the bases labeled (A). (B), (C) and (D), which one can effectively deprotonate this compound? (A) H₂O H3C CH3 acetone H3C- (A) 2 (A) NaCN (B) pKa (CH3)3COH = 19 pKa HCN = 9 + B (B) 3 12 Whiska -OK CH3 CI C=CH-CHCH3 å (C) 4 (D) 8 H₂C (A) A and D (B) only A (C) only B (D) only C 11. How many stereoisomers are possible for the molecule shown below? CH₂ NaNhz (C) pKaNH = 38 + B-H NaOH (D) pKa H₂O = 16

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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Which of the following molecules cannot act as a nucleophile?
(B) N
(C) BIL,
(D) PH,
10. Given that the pKa of acetone is 19, of the bases labeled (A). (B). (C) and (D), which one can effectively deprotonate this
compound?
(A) H₂O
H3C
acetone
H3C-
CH3
H3C
H
Br
>
(A)
NaCN
(B)
pKa (CH3)3COH = 19 pKa HCN = 9
+ B
CH₂
H3C. H
HY H
Br
(A)
(A) A and D
(B) only A
(C) only B
(D) only C
11. How many stereoisomers are possible for the molecule shown below?
H
H
OK
CH3
CH3 CI
C=CH-CHCH3
(A) 2 (B) 3 (C) 4 (D) 8
12. Which Newman projection does not represent a different conformation of the molecule shown in the box?
CH3
CH3
H
Br ΤΗ
H
H3C
H
CH3
H₂C CH₂ +
H
NaNHz
(C)
pKa NH3 = 38
6
Br
H
H
NaOH
(D)
pKa H₂O = 16
H
B-H
CH3
CH3
H
Br
(D)
Transcribed Image Text:Which of the following molecules cannot act as a nucleophile? (B) N (C) BIL, (D) PH, 10. Given that the pKa of acetone is 19, of the bases labeled (A). (B). (C) and (D), which one can effectively deprotonate this compound? (A) H₂O H3C acetone H3C- CH3 H3C H Br > (A) NaCN (B) pKa (CH3)3COH = 19 pKa HCN = 9 + B CH₂ H3C. H HY H Br (A) (A) A and D (B) only A (C) only B (D) only C 11. How many stereoisomers are possible for the molecule shown below? H H OK CH3 CH3 CI C=CH-CHCH3 (A) 2 (B) 3 (C) 4 (D) 8 12. Which Newman projection does not represent a different conformation of the molecule shown in the box? CH3 CH3 H Br ΤΗ H H3C H CH3 H₂C CH₂ + H NaNHz (C) pKa NH3 = 38 6 Br H H NaOH (D) pKa H₂O = 16 H B-H CH3 CH3 H Br (D)
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