Which of the following lines is perpendicular to y= -5x-2? O y = 1/5x + 1/5 O y = 5x - 1 O y = -5x + 5 O y = 2/5x + 3

Elementary Geometry For College Students, 7e
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ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
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**Question 18: Which of the following lines is perpendicular to \( y = -5x - 2 \)?**

- \( \bigcirc \) \( y = \frac{1}{5}x + \frac{1}{5} \)
- \( \bigcirc \) \( y = 5x - 1 \)
- \( \bigcirc \) \( y = -5x + 5 \)
- \( \bigcirc \) \( y = \frac{2}{5}x + 3 \)

**Explanation:**

For two lines to be perpendicular, the product of their slopes must be -1.

The slope of the given line \( y = -5x - 2 \) is -5.

To find the slope \( m_1 \) of a line perpendicular to this, use the formula:

\[ m \times m_1 = -1 \]

Substituting the known slope:

\[ -5 \times m_1 = -1 \]

Solving for \( m_1 \):

\[ m_1 = \frac{1}{5} \]

Thus, the line with the slope \( \frac{1}{5} \) is perpendicular to \( y = -5x - 2 \).

The correct choice is:

- \( \bigcirc \) \( y = \frac{1}{5}x + \frac{1}{5} \)
Transcribed Image Text:**Question 18: Which of the following lines is perpendicular to \( y = -5x - 2 \)?** - \( \bigcirc \) \( y = \frac{1}{5}x + \frac{1}{5} \) - \( \bigcirc \) \( y = 5x - 1 \) - \( \bigcirc \) \( y = -5x + 5 \) - \( \bigcirc \) \( y = \frac{2}{5}x + 3 \) **Explanation:** For two lines to be perpendicular, the product of their slopes must be -1. The slope of the given line \( y = -5x - 2 \) is -5. To find the slope \( m_1 \) of a line perpendicular to this, use the formula: \[ m \times m_1 = -1 \] Substituting the known slope: \[ -5 \times m_1 = -1 \] Solving for \( m_1 \): \[ m_1 = \frac{1}{5} \] Thus, the line with the slope \( \frac{1}{5} \) is perpendicular to \( y = -5x - 2 \). The correct choice is: - \( \bigcirc \) \( y = \frac{1}{5}x + \frac{1}{5} \)
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