Write the equation of the line PERPENDICULAR to 3y – 2x = 6 passing through (5, -8)

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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**Problem Statement**

Write the equation of the line perpendicular to \(3y - 2x = 6\) passing through the point \((5, -8)\).

**Explanation**

To find the equation of a line that is perpendicular to a given line, follow these steps:

1. **Convert the Standard Form to Slope-Intercept Form:**  
   The equation \(3y - 2x = 6\) can be rewritten in slope-intercept form (\(y = mx + b\)) to find the slope.
   - Rearrange the terms to isolate \(y\):  
     \(3y = 2x + 6\)
   - Divide by 3:  
     \(y = \frac{2}{3}x + 2\)

   The slope (\(m\)) of the given line is \(\frac{2}{3}\).

2. **Find the Perpendicular Slope:**  
   The slope of a line perpendicular to another is the negative reciprocal.  
   - The negative reciprocal of \(\frac{2}{3}\) is \(-\frac{3}{2}\).

3. **Use the Point-Slope Form to Determine the Equation:**  
   With the perpendicular slope \(-\frac{3}{2}\) and the point \((5, -8)\), use the point-slope form \(y - y_1 = m(x - x_1)\).
   - Substitute: \(y + 8 = -\frac{3}{2}(x - 5)\)

4. **Convert to Slope-Intercept Form if Needed:**  
   Solve for \(y\) to convert the equation to slope-intercept form:
   - Expand: \(y + 8 = -\frac{3}{2}x + \frac{15}{2}\)
   - Isolate \(y\):  
     \(y = -\frac{3}{2}x + \frac{15}{2} - 8\)
   - Simplify:  
     \(y = -\frac{3}{2}x - \frac{1}{2}\)

The equation of the line perpendicular to \(3y - 2x = 6\) passing through \((5, -8)\) is \(y = -\frac{3}{2}x - \frac{1}{2}\).
Transcribed Image Text:**Problem Statement** Write the equation of the line perpendicular to \(3y - 2x = 6\) passing through the point \((5, -8)\). **Explanation** To find the equation of a line that is perpendicular to a given line, follow these steps: 1. **Convert the Standard Form to Slope-Intercept Form:** The equation \(3y - 2x = 6\) can be rewritten in slope-intercept form (\(y = mx + b\)) to find the slope. - Rearrange the terms to isolate \(y\): \(3y = 2x + 6\) - Divide by 3: \(y = \frac{2}{3}x + 2\) The slope (\(m\)) of the given line is \(\frac{2}{3}\). 2. **Find the Perpendicular Slope:** The slope of a line perpendicular to another is the negative reciprocal. - The negative reciprocal of \(\frac{2}{3}\) is \(-\frac{3}{2}\). 3. **Use the Point-Slope Form to Determine the Equation:** With the perpendicular slope \(-\frac{3}{2}\) and the point \((5, -8)\), use the point-slope form \(y - y_1 = m(x - x_1)\). - Substitute: \(y + 8 = -\frac{3}{2}(x - 5)\) 4. **Convert to Slope-Intercept Form if Needed:** Solve for \(y\) to convert the equation to slope-intercept form: - Expand: \(y + 8 = -\frac{3}{2}x + \frac{15}{2}\) - Isolate \(y\): \(y = -\frac{3}{2}x + \frac{15}{2} - 8\) - Simplify: \(y = -\frac{3}{2}x - \frac{1}{2}\) The equation of the line perpendicular to \(3y - 2x = 6\) passing through \((5, -8)\) is \(y = -\frac{3}{2}x - \frac{1}{2}\).
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