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Which of the following is closest to the time for the object to reach the maximum height? а. 274.0s b. 95.00s c. 0.3473s d. 9.517s Which of the following is closest to the maximum height? hint: s = Svdt а. 32.38m b. 15100m c. 449.4m d. 16.40m

Which of the following is closest to the time for the object to reach the maximum height? а. 274.0s b. 95.00s c. 0.3473s d. 9.517s Which of the following is closest to the maximum height? hint: s = Svdt а. 32.38m b. 15100m c. 449.4m d. 16.40m

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Can you please answer numbers 4 and 5? Thank you!

An object with a mass of 10.00kg is launched from the ground with an initial upward velocity of 95.00m/s near the surface of Earth. Consider a linear model of the air resistance, kv, with v being the variable velocity and k = 0.0365 kg/s?. Take the ground as the origin and upwards as positive direction. Which of the following best describes the DE relating to the problem? Let t be the time, g be the acceleration due to gravity. a. -10.00- 3.285 = 10.00 dv/dt b. -10.00g +0.0365v = 10.00 dv/dt c. -10.00g - 0.0365v = 10.00 đv/dt d. -10.00g – 3.285 = -10.00dv/dt Which of the following is closest to the general solution of the linear DE model, velocity as a function of time? Let C be a real constant, exp()=e0 a. v(t) = 1.346t + C b. v(t) = -2688+Cexp(t/274.0) c. v(t) = -2688+Cexp(-1/10.00) d. v(t) = -2688+Cexp(-1/274.0) Which of the following is closest to the exact solution? a. t) = -2688+2783exp(-t/274.0) b. t) = -2688+2783exp(-t/10.00) c. t) = -2688+2783exp(t/274.0) d. t) = 1.346t + 95.00 Which of the following is closest to the time for the object to reach the maximum height? a. 274.0s b. 95.00s c. 0.3473s d. 9.517s Which of the following is closest to the maximum height? hint: s = S vdt а. 32.38m b. 15100m c. 449.4m d. 16.40m
Transcribed Image Text:An object with a mass of 10.00kg is launched from the ground with an initial upward velocity of 95.00m/s near the surface of Earth. Consider a linear model of the air resistance, kv, with v being the variable velocity and k = 0.0365 kg/s?. Take the ground as the origin and upwards as positive direction. Which of the following best describes the DE relating to the problem? Let t be the time, g be the acceleration due to gravity. a. -10.00- 3.285 = 10.00 dv/dt b. -10.00g +0.0365v = 10.00 dv/dt c. -10.00g - 0.0365v = 10.00 đv/dt d. -10.00g – 3.285 = -10.00dv/dt Which of the following is closest to the general solution of the linear DE model, velocity as a function of time? Let C be a real constant, exp()=e0 a. v(t) = 1.346t + C b. v(t) = -2688+Cexp(t/274.0) c. v(t) = -2688+Cexp(-1/10.00) d. v(t) = -2688+Cexp(-1/274.0) Which of the following is closest to the exact solution? a. t) = -2688+2783exp(-t/274.0) b. t) = -2688+2783exp(-t/10.00) c. t) = -2688+2783exp(t/274.0) d. t) = 1.346t + 95.00 Which of the following is closest to the time for the object to reach the maximum height? a. 274.0s b. 95.00s c. 0.3473s d. 9.517s Which of the following is closest to the maximum height? hint: s = S vdt а. 32.38m b. 15100m c. 449.4m d. 16.40m
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