Which of the following integrals will solve for the current through the rectangular surface defined by p=37°, 2≤p≤5, -3≤z≤ 4 if the current density is 1 -sin2 apza A/m2? The coordinates and z are measured in meters. J=-=-=p²cos² pa 1 a+p- P O O O 1 SS² 2 1 SS². -3 2 40% 1 5 SS³. -3 2 180 2 30²cos ² 40л 180 -pz.pdpdz sin 2 .pdpdz 40% 180 Z .pdpdz O (The answer cannot be found on the other choices.)
Which of the following integrals will solve for the current through the rectangular surface defined by p=37°, 2≤p≤5, -3≤z≤ 4 if the current density is 1 -sin2 apza A/m2? The coordinates and z are measured in meters. J=-=-=p²cos² pa 1 a+p- P O O O 1 SS² 2 1 SS². -3 2 40% 1 5 SS³. -3 2 180 2 30²cos ² 40л 180 -pz.pdpdz sin 2 .pdpdz 40% 180 Z .pdpdz O (The answer cannot be found on the other choices.)
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Transcribed Image Text:Which of the following integrals will solve for the current through the rectangular surface defined by p=37°, 2<p ≤5, -3<< < 4 if the current density is
1
=p³cos²₁ +₁
+ 12/0²/14 - 12/25
J=
O
O
O
P
1
S²S²=-=p²cos² =
-3 2
SS³-
-3 2
[[ ²² (180 + 2 sin (2-180))
40л
180
--sin2 a - pz a A/m²? The coordinates p and z are measured in meters.
-pz.pdp dz
$
.pdpdz
.pdpdz
O (The answer cannot be found on the other choices.)
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