The magnitude J of the current density in a certain wire with a circular cross section of radius R = 2.00 mm is given by J = (3.34 x 108)r², with Jin amperes per square meter and radial distance r in meters. What is the current through the outer section bounded by r = 0.926R and r = R? Number i 2.392 Units mA

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**Problem Statement:**

The magnitude \( J \) of the current density in a certain wire with a circular cross section of radius \( R = 2.00 \text{ mm} \) is given by:

\[ J = (3.34 \times 10^8) r^2 \]

where \( J \) is in amperes per square meter and \( r \) is the radial distance in meters. What is the current through the outer section bounded by \( r = 0.926R \) and \( r = R \)?

**Input Fields:**
- **Number:** 2.392
- **Units:** mA

To solve this problem, we need to integrate the current density \( J \) over the specified area to find the total current \( I \) passing through the outer section of the wire. The approach involves setting up and evaluating an integral with the given limits.
Transcribed Image Text:**Problem Statement:** The magnitude \( J \) of the current density in a certain wire with a circular cross section of radius \( R = 2.00 \text{ mm} \) is given by: \[ J = (3.34 \times 10^8) r^2 \] where \( J \) is in amperes per square meter and \( r \) is the radial distance in meters. What is the current through the outer section bounded by \( r = 0.926R \) and \( r = R \)? **Input Fields:** - **Number:** 2.392 - **Units:** mA To solve this problem, we need to integrate the current density \( J \) over the specified area to find the total current \( I \) passing through the outer section of the wire. The approach involves setting up and evaluating an integral with the given limits.
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