Which of the following has optical isomers? Explain your answer a) Square planar- [Pb(OH)Br₂l ]²- b) Square planar- [Zn(en)Cl₂] c) Trans-[Cr(NH3)2C14]3 For the toolbar, press ALT+F10 (PC) or ALT+FN+F10 (Mac). BIUS Paragraph V Arial 14px
Which of the following has optical isomers? Explain your answer a) Square planar- [Pb(OH)Br₂l ]²- b) Square planar- [Zn(en)Cl₂] c) Trans-[Cr(NH3)2C14]3 For the toolbar, press ALT+F10 (PC) or ALT+FN+F10 (Mac). BIUS Paragraph V Arial 14px
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Which of the following has optical isomers? Explain your answer**
a) Square planar - \([Pb(OH)Br_2]^{2-}\)
b) Square planar - \([Zn(en)Cl_2]\)
c) Trans - \([Cr(NH_3)_2Cl_4]^3\)
(Note: \(en\) stands for ethylenediamine, which is a bidentate ligand)
**Explanation:**
**a) Square planar - \([Pb(OH)Br_2]^{2-}\)**
Square planar complexes do not typically exhibit optical isomerism because their planar structure can be superimposed on its mirror image. Optical isomerism requires chirality, which is absent in this geometry.
**b) Square planar - \([Zn(en)Cl_2]\)**
In this case, the molecule has ethylenediamine (en) as a bidentate ligand. Square planar structures with bidentate ligands can have non-superimposable mirror images, leading to optical isomerism. Therefore, this complex is optically active.
**c) Trans - \([Cr(NH_3)_2Cl_4]^3\)**
The trans configuration in octahedral complexes places the same ligands opposite each other. As a result, the complex is symmetrical and cannot be chiral. Therefore, this complex does not have optical isomers.
**Conclusion:**
The correct answer is **b) Square planar - \([Zn(en)Cl_2]\)** since this complex is capable of exhibiting optical isomerism due to its structure with bidentate ligands.
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Transcribed Image Text:**Which of the following has optical isomers? Explain your answer**
a) Square planar - \([Pb(OH)Br_2]^{2-}\)
b) Square planar - \([Zn(en)Cl_2]\)
c) Trans - \([Cr(NH_3)_2Cl_4]^3\)
(Note: \(en\) stands for ethylenediamine, which is a bidentate ligand)
**Explanation:**
**a) Square planar - \([Pb(OH)Br_2]^{2-}\)**
Square planar complexes do not typically exhibit optical isomerism because their planar structure can be superimposed on its mirror image. Optical isomerism requires chirality, which is absent in this geometry.
**b) Square planar - \([Zn(en)Cl_2]\)**
In this case, the molecule has ethylenediamine (en) as a bidentate ligand. Square planar structures with bidentate ligands can have non-superimposable mirror images, leading to optical isomerism. Therefore, this complex is optically active.
**c) Trans - \([Cr(NH_3)_2Cl_4]^3\)**
The trans configuration in octahedral complexes places the same ligands opposite each other. As a result, the complex is symmetrical and cannot be chiral. Therefore, this complex does not have optical isomers.
**Conclusion:**
The correct answer is **b) Square planar - \([Zn(en)Cl_2]\)** since this complex is capable of exhibiting optical isomerism due to its structure with bidentate ligands.
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