**Which of the following has optical isomers? Explain your answer**a) Square planar - \([Pb(OH)Br_2]^{2-}\)b) Square planar - \([Zn(en)Cl_2]\)c) Trans - \([Cr(NH_3)_2Cl_4]^3\)(Note: \(en\) stands for ethylenediamine, which is a bidentate ligand)**Explanation:****a) Square planar - \([Pb(OH)Br_2]^{2-}\)**Square planar complexes do not typically exhibit optical isomerism because their planar structure can be superimposed on its mirror image. Optical isomerism requires chirality, which is absent in this geometry.**b) Square planar - \([Zn(en)Cl_2]\)**In this case, the molecule has ethylenediamine (en) as a bidentate ligand. Square planar structures with bidentate ligands can have non-superimposable mirror images, leading to optical isomerism. Therefore, this complex is optically active.**c) Trans - \([Cr(NH_3)_2Cl_4]^3\)**The trans configuration in octahedral complexes places the same ligands opposite each other. As a result, the complex is symmetrical and cannot be chiral. Therefore, this complex does not have optical isomers.**Conclusion:**The correct answer is **b) Square planar - \([Zn(en)Cl_2]\)** since this complex is capable of exhibiting optical isomerism due to its structure with bidentate ligands.---**Further Explanation on the Toolbar:**For the toolbar, press **ALT+F10 (PC)** or **ALT+FN+F10 (Mac)**. **Toolbar Options:**- **B:** Bold- **I:** Italics- **U:** Underline- **S:** Strikethrough- **Paragraph Options:** Allows selection of paragraph alignment and indentation.- **Font Options:** Allows changing the font type and size, in this example, it's set to Arial, 14px.This toolbar information can assist in formatting your document correctly while editing.

For optical isomerism there should be no plane of symmetry in complex.

Which of the following has optical isomers? Explain your answer a) Square planar- [Pb(OH)Br₂l ]²- b) Square planar- [Zn(en)Cl₂] c) Trans-[Cr(NH3)2C14]3 For the toolbar, press ALT+F10 (PC) or ALT+FN+F10 (Mac). BIUS Paragraph V Arial 14px

Which of the following has optical isomers? Explain your answer a) Square planar- [Pb(OH)Br₂l ]²- b) Square planar- [Zn(en)Cl₂] c) Trans-[Cr(NH3)2C14]3 For the toolbar, press ALT+F10 (PC) or ALT+FN+F10 (Mac). BIUS Paragraph V Arial 14px

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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