Which of the following equations could be used to find the height of the obtuse triangle shown? Select all that apply. A B h sin (180° - A) = h sin B = cos (180° ☐ A) = b h Osin A = cos A = h b h b

Elementary Geometry For College Students, 7e
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Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
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ChapterP: Preliminary Concepts
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## Finding the Height of an Obtuse Triangle

### Problem Statement
Which of the following equations could be used to find the height of the obtuse triangle shown? Select all that apply.

### Triangle Diagram

The image depicts an obtuse triangle \( \triangle ABC \) with the following properties:
- \( \angle A \) is acute, and the triangle extends such that \( \angle C \) is obtuse.
- Side \( a \) is opposite to \( \angle A \), side \( b \) is opposite to \( \angle B \), and side \( c \) is opposite to \( \angle C \).
- \( h \) is the height from vertex \( C \) perpendicular to the line extending from side \( AB \).

### Given Equations

1. \(\sin(180^\circ - A) = \frac{h}{b}\)
2. \(\sin B = \frac{h}{a}\)
3. \(\cos(180^\circ - A) = \frac{h}{b}\)
4. \(\sin A = \frac{h}{b}\)
5. \(\cos A = \frac{h}{b}\)

### Solution Explanation

In order to find the height \( h \), you need to use trigonometric relationships involving the given angles and sides.

- \(\sin(180^\circ - A) = \sin A\). Thus, \(\sin(180^\circ - A) = \frac{h}{b}\) can be rewritten as \(\sin A = \frac{h}{b}\), which matches one of the given equations.
- The equation \(\sin B = \frac{h}{a}\) involves angle \( B \) and side \( a \), but for angle \( B \) to be usable it must be an angle in a different position relative to height \( h \).
- \(\cos(180^\circ - A) = -\cos A\), typically can resolve into a different trigonometric relationship, and may not directly help in finding \( h \).

### Correct Options
The correct equations that can be used to find the height \( h \) are:

1. \(\sin(180^\circ - A) = \frac{h}{b}\)
2. \(\sin A = \frac{h}{b}\)

Both of these relationships can be simplified to form a
Transcribed Image Text:## Finding the Height of an Obtuse Triangle ### Problem Statement Which of the following equations could be used to find the height of the obtuse triangle shown? Select all that apply. ### Triangle Diagram The image depicts an obtuse triangle \( \triangle ABC \) with the following properties: - \( \angle A \) is acute, and the triangle extends such that \( \angle C \) is obtuse. - Side \( a \) is opposite to \( \angle A \), side \( b \) is opposite to \( \angle B \), and side \( c \) is opposite to \( \angle C \). - \( h \) is the height from vertex \( C \) perpendicular to the line extending from side \( AB \). ### Given Equations 1. \(\sin(180^\circ - A) = \frac{h}{b}\) 2. \(\sin B = \frac{h}{a}\) 3. \(\cos(180^\circ - A) = \frac{h}{b}\) 4. \(\sin A = \frac{h}{b}\) 5. \(\cos A = \frac{h}{b}\) ### Solution Explanation In order to find the height \( h \), you need to use trigonometric relationships involving the given angles and sides. - \(\sin(180^\circ - A) = \sin A\). Thus, \(\sin(180^\circ - A) = \frac{h}{b}\) can be rewritten as \(\sin A = \frac{h}{b}\), which matches one of the given equations. - The equation \(\sin B = \frac{h}{a}\) involves angle \( B \) and side \( a \), but for angle \( B \) to be usable it must be an angle in a different position relative to height \( h \). - \(\cos(180^\circ - A) = -\cos A\), typically can resolve into a different trigonometric relationship, and may not directly help in finding \( h \). ### Correct Options The correct equations that can be used to find the height \( h \) are: 1. \(\sin(180^\circ - A) = \frac{h}{b}\) 2. \(\sin A = \frac{h}{b}\) Both of these relationships can be simplified to form a
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