Which of the following describes method overloading? O Amethod with the same name buta different number or type of anguments O Amethod defined in the subclass with the same signaturc (return type and arguments) as the inherited method. O A method that contains too much code for a single method.

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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Which of the following describes method overloading?
O A method with the same name buta different number or type of arguments
O A method defined in the subclass with the same signature (retum type and arguments) as the inherited
method.
O A method that contains too much code for a single method.
Transcribed Image Text:Which of the following describes method overloading? O A method with the same name buta different number or type of arguments O A method defined in the subclass with the same signature (retum type and arguments) as the inherited method. O A method that contains too much code for a single method.
Expert Solution
Step 1

Introduction of the Method Overloading:

In any programming language if the function has the same name but a different type of argument or parameter then it is called method overloading or function overloading. The compiler distinguishes the method through its parameter means if a method has one integer datatype, and the other has two integer data type as a parameter, and the other has one integer and one double datatype.

Step 2

Example of the Method overloading: save the below code as main.cpp

//main.cpp
#include <iostream> //header file for cin,cout and endl
using namespace std;

//method has one integer datatyps 
void print(int num) { 
  cout << " Here is int " << num<< endl; 

//method has one double datatype
void print(double num) { 
  cout << " Here is float " << num << endl; 
}
//method has two integer datatype 
void print(int num1, int num2) { 
  cout << " Sum is " << (num1+num2)<< endl; 

  
int main() { 
  print(10); 
  print(10.10); 
  print(10,20); 
  return 0; 
}

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