Which of the following compounds has an "arrowed" carbon atom that is sp2 hybridized? A C H₂C=C=CH₂ CH3 H₂C-C-CH₂ NH B H₂C-C-CH3 D Compounds B and C

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## Question on Hybridization

**Question:** Which of the following compounds has an “arrowed” carbon atom that is sp² hybridized?

### Descriptions of Each Option:

- **Option A:**
  
  \[
  \text{H}_2\text{C} = \text{C} = \text{CH}_2
  \]

  The arrow points to the central carbon atom in a structure where two hydrogen atoms are single-bonded to a carbon atom. This carbon atom is double-bonded to another carbon atom, which is again double-bonded to a third carbon atom, which is single-bonded to two hydrogen atoms.

- **Option B:**
  
  \[
  \text{H}_3\text{C} - \text{C} = \text{N}
  \]
  
  The arrow points to a carbon atom that is single-bonded to a nitrogen atom (which is single-bonded to a hydrogen atom) and double-bonded to another carbon atom, which is single-bonded to three hydrogen atoms.

- **Option C:**
  
  \[
  \text{H}_3\text{C} - \text{C} - \text{CH}_3
  \]
  
  The arrow points to the central carbon atom that is single-bonded to two other carbon atoms, each of which is single-bonded to three hydrogen atoms.

- **Option D:**
  
  \[
  \text{Compounds B and C}
  \]
  
  This option suggests that both compounds B and C might have the arrowed carbon atom in the specified hybridization state.

### Analysis:
The hybridization of a carbon atom depends on the types of bonds it forms:

- **sp³ hybridization:** Carbon forms four single bonds.
- **sp² hybridization:** Carbon forms one double bond and two single bonds.
- **sp hybridization:** Carbon forms triple bonds or two double bonds.

Based on this understanding:
- In **Option A**, the central carbon atom has two double bonds. Therefore, it is sp hybridized.
- In **Option B**, the arrowed carbon atom forms a double bond and two single bonds, indicating sp² hybridization.
- In **Option C**, the arrowed carbon atom forms four single bonds, indicating sp³ hybridization.

So, the correct answer is:

**Option B:**
Transcribed Image Text:## Question on Hybridization **Question:** Which of the following compounds has an “arrowed” carbon atom that is sp² hybridized? ### Descriptions of Each Option: - **Option A:** \[ \text{H}_2\text{C} = \text{C} = \text{CH}_2 \] The arrow points to the central carbon atom in a structure where two hydrogen atoms are single-bonded to a carbon atom. This carbon atom is double-bonded to another carbon atom, which is again double-bonded to a third carbon atom, which is single-bonded to two hydrogen atoms. - **Option B:** \[ \text{H}_3\text{C} - \text{C} = \text{N} \] The arrow points to a carbon atom that is single-bonded to a nitrogen atom (which is single-bonded to a hydrogen atom) and double-bonded to another carbon atom, which is single-bonded to three hydrogen atoms. - **Option C:** \[ \text{H}_3\text{C} - \text{C} - \text{CH}_3 \] The arrow points to the central carbon atom that is single-bonded to two other carbon atoms, each of which is single-bonded to three hydrogen atoms. - **Option D:** \[ \text{Compounds B and C} \] This option suggests that both compounds B and C might have the arrowed carbon atom in the specified hybridization state. ### Analysis: The hybridization of a carbon atom depends on the types of bonds it forms: - **sp³ hybridization:** Carbon forms four single bonds. - **sp² hybridization:** Carbon forms one double bond and two single bonds. - **sp hybridization:** Carbon forms triple bonds or two double bonds. Based on this understanding: - In **Option A**, the central carbon atom has two double bonds. Therefore, it is sp hybridized. - In **Option B**, the arrowed carbon atom forms a double bond and two single bonds, indicating sp² hybridization. - In **Option C**, the arrowed carbon atom forms four single bonds, indicating sp³ hybridization. So, the correct answer is: **Option B:**
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