Which of the following blocks of code will output "yes" if the String inputLine starts with "y" ? if(inputline.charat(e) = "y") System.out.println("yes"); if(inputline.charat(1) == 'y') System.out.println(“yes"); if(inputline[e] == "y") System.out.println("yes"); O if(inputline.charat(e) == 'y') System.out.println("yes"); if(inputline == "y") System.out.printin("yes");

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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**Question:**  
Which of the following blocks of code will output “yes” if the String `inputLine` starts with “y”?  

**Code Options:**

1. 
   ```java
   if(inputLine.charAt(0) = "y")
       System.out.println("yes");
   ```

2. 
   ```java
   if(inputLine.charAt(1) == 'y')
       System.out.println("yes");
   ```

3. 
   ```java
   if(inputLine[0] == "y")
       System.out.println("yes");
   ```

4. 
   ```java
   if(inputLine.charAt(0) == 'y')
       System.out.println("yes");
   ```

5. 
   ```java
   if(inputLine == "y")
       System.out.println("yes");
   ```

**Explanation:**  
The task is to determine which code correctly checks if the first character of the string `inputLine` is 'y' and outputs "yes" if true. Option 4 is correct because it uses `charAt(0)` to access the first character and compares it with the character 'y' using the equality operator `==`.
Transcribed Image Text:**Question:** Which of the following blocks of code will output “yes” if the String `inputLine` starts with “y”? **Code Options:** 1. ```java if(inputLine.charAt(0) = "y") System.out.println("yes"); ``` 2. ```java if(inputLine.charAt(1) == 'y') System.out.println("yes"); ``` 3. ```java if(inputLine[0] == "y") System.out.println("yes"); ``` 4. ```java if(inputLine.charAt(0) == 'y') System.out.println("yes"); ``` 5. ```java if(inputLine == "y") System.out.println("yes"); ``` **Explanation:** The task is to determine which code correctly checks if the first character of the string `inputLine` is 'y' and outputs "yes" if true. Option 4 is correct because it uses `charAt(0)` to access the first character and compares it with the character 'y' using the equality operator `==`.
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