Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Question:**
Which of the alkenes shown below can't be assigned as an E or Z isomer?
**Structures:**
(a) ![Figure a](structure_a.jpg) \
(b) ![Figure b](structure_b.jpg) \
(c) ![Figure c](structure_c.jpg) \
(d) ![Figure d](structure_d.jpg) \
(e) ![Figure e](structure_e.jpg)
**Options:**
- O b, c, e
- O a, c, e
- O a, c, d
- O a, b, d
- O b, d, e
**Explanation:**
Each structure is an alkene (a carbon-carbon double bond). E/Z isomerism, also known as cis/trans isomerism, occurs when each carbon of the double bond is attached to two different groups, making it possible to have different spatial arrangements of these groups. Here we will analyze the structures to determine which ones can be assigned as E or Z isomers:
- **Structure (a)**: This is a simple alkene with identical groups attached to one of the carbons of the double bond. E/Z isomerism is not applicable here.
- **Structure (b)**: This structure has different substituents (Cl and Br) on both carbons of the double bond, making it possible to assign E/Z isomers.
- **Structure (c)**: Similar to structure (a), this alkene has identical groups on one of the carbons, meaning E/Z isomerism is not applicable.
- **Structure (d)**: This structure has unique substituents on each carbon of the double bond, allowing for E/Z isomerism assignment.
- **Structure (e)**: This is a cyclic alkene where the spatial arrangements of substituents around the double bond do not lead to E/Z isomerism.
**Answer:**
- The correct answer is **b, c, e**.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd4844e47-8bac-47db-9d5f-a634c5eb0fa3%2F7c462a40-c5ab-4a29-b0cd-f80213c3a93c%2Fuygbs9_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Question:**
Which of the alkenes shown below can't be assigned as an E or Z isomer?
**Structures:**
(a) ![Figure a](structure_a.jpg) \
(b) ![Figure b](structure_b.jpg) \
(c) ![Figure c](structure_c.jpg) \
(d) ![Figure d](structure_d.jpg) \
(e) ![Figure e](structure_e.jpg)
**Options:**
- O b, c, e
- O a, c, e
- O a, c, d
- O a, b, d
- O b, d, e
**Explanation:**
Each structure is an alkene (a carbon-carbon double bond). E/Z isomerism, also known as cis/trans isomerism, occurs when each carbon of the double bond is attached to two different groups, making it possible to have different spatial arrangements of these groups. Here we will analyze the structures to determine which ones can be assigned as E or Z isomers:
- **Structure (a)**: This is a simple alkene with identical groups attached to one of the carbons of the double bond. E/Z isomerism is not applicable here.
- **Structure (b)**: This structure has different substituents (Cl and Br) on both carbons of the double bond, making it possible to assign E/Z isomers.
- **Structure (c)**: Similar to structure (a), this alkene has identical groups on one of the carbons, meaning E/Z isomerism is not applicable.
- **Structure (d)**: This structure has unique substituents on each carbon of the double bond, allowing for E/Z isomerism assignment.
- **Structure (e)**: This is a cyclic alkene where the spatial arrangements of substituents around the double bond do not lead to E/Z isomerism.
**Answer:**
- The correct answer is **b, c, e**.
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