Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Question
![**Question 12 of 12**
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---
**Current Attempt in Progress**
*Your answer is incorrect.*
**Which numbers are a solution to \((x + 1)^2 - 1 = 0\)?**
- [ ] \(-4\)
- [ ] \(-2\)
- [x] \(0\)
- [ ] \(2\)
- [ ] \(4\)
---
**eTextbook and Media**
**Hint**
---
### Explanation:
To solve the equation \((x + 1)^2 - 1 = 0\), follow these steps:
1. **Start with the given equation:**
\[
(x + 1)^2 - 1 = 0
\]
2. **Add 1 to both sides:**
\[
(x + 1)^2 = 1
\]
3. **Take the square root of both sides:**
\[
x + 1 = \pm1
\]
4. **Solve for \(x\):**
- \(x + 1 = 1 \Rightarrow x = 0\)
- \(x + 1 = -1 \Rightarrow x = -2\)
Thus, the solutions are \(x = 0\) and \(x = -2\).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F35303b46-695e-415e-bf0a-724431d4b4c3%2Fa3fd4083-b4b4-49c5-90c8-57a51b8647a3%2F3jes7j_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Question 12 of 12**
- **View Policies**
- **Show Attempt History**
---
**Current Attempt in Progress**
*Your answer is incorrect.*
**Which numbers are a solution to \((x + 1)^2 - 1 = 0\)?**
- [ ] \(-4\)
- [ ] \(-2\)
- [x] \(0\)
- [ ] \(2\)
- [ ] \(4\)
---
**eTextbook and Media**
**Hint**
---
### Explanation:
To solve the equation \((x + 1)^2 - 1 = 0\), follow these steps:
1. **Start with the given equation:**
\[
(x + 1)^2 - 1 = 0
\]
2. **Add 1 to both sides:**
\[
(x + 1)^2 = 1
\]
3. **Take the square root of both sides:**
\[
x + 1 = \pm1
\]
4. **Solve for \(x\):**
- \(x + 1 = 1 \Rightarrow x = 0\)
- \(x + 1 = -1 \Rightarrow x = -2\)
Thus, the solutions are \(x = 0\) and \(x = -2\).
Expert Solution
Step 1: Determined the given data
Given :- (x + 1)2 - 1 = 0
Now,
(x + 1)2 = 1
Step by step
Solved in 3 steps with 1 images
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