then A-1 A 7 -8

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
Question
**Matrix Inversion Example**

Given the matrix \(A\):

\[ A = \begin{bmatrix} 7 & -8 \\ -8 & -1 \end{bmatrix} ,\]

then,

\[ A^{-1} = \begin{bmatrix} \boxed{} & \boxed{} \\ \boxed{} & \boxed{} \end{bmatrix} .\]

In this example, we are given a 2x2 matrix \(A\) and are asked to find its inverse \(A^{-1}\). To calculate the inverse of a 2x2 matrix:

\[ A = \begin{bmatrix} a & b \\ c & d \end{bmatrix} ,\]

the inverse is given by:

\[ A^{-1} = \frac{1}{ad - bc} \begin{bmatrix} d & -b \\ -c & a \end{bmatrix} ,\]

provided that \(ad - bc \neq 0\). This determinant \(ad - bc\) must be non-zero for the inverse to exist.

In the given matrix:

\[ A = \begin{bmatrix} 7 & -8 \\ -8 & -1 \end{bmatrix} ,\]

we would identify \( a = 7, b = -8, c = -8,\) and \(d = -1\) and apply the formula accordingly.
Transcribed Image Text:**Matrix Inversion Example** Given the matrix \(A\): \[ A = \begin{bmatrix} 7 & -8 \\ -8 & -1 \end{bmatrix} ,\] then, \[ A^{-1} = \begin{bmatrix} \boxed{} & \boxed{} \\ \boxed{} & \boxed{} \end{bmatrix} .\] In this example, we are given a 2x2 matrix \(A\) and are asked to find its inverse \(A^{-1}\). To calculate the inverse of a 2x2 matrix: \[ A = \begin{bmatrix} a & b \\ c & d \end{bmatrix} ,\] the inverse is given by: \[ A^{-1} = \frac{1}{ad - bc} \begin{bmatrix} d & -b \\ -c & a \end{bmatrix} ,\] provided that \(ad - bc \neq 0\). This determinant \(ad - bc\) must be non-zero for the inverse to exist. In the given matrix: \[ A = \begin{bmatrix} 7 & -8 \\ -8 & -1 \end{bmatrix} ,\] we would identify \( a = 7, b = -8, c = -8,\) and \(d = -1\) and apply the formula accordingly.
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