Which is true?Using a non-random sample does not affect the accuracy of a confidence interval.Our method requires that the sample size must be less than 10% of the population we are investigating.The value of p depends on our sample.It is more likely that p is near the middle of a confidence interval than near the edges.Previous#3edCC$4rf>urolo%5tOll6DELLby9 h&70CJ★800jOi3(9k✓O)VO

Given data : Which of is the following is true?

Answered: Which is true? Using a non-random…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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arly-childhood-development studies indicate that the more often a child is read to from birth, the earlier the child begins to read. A local parents’ group wants to test this theory and samples families with young children. They find the following results. Construct a 90% confidence interval to estimate the true difference between the proportions of children who read at an early age when they are read to frequently compared to those who were read to less often, as described in the table of results. Let Population 1 be the children who were read to frequently and Population 2 be the children who were read to less often. Round the endpoints of the interval to three decimal places, if necessary. Ages when Children Begin to Read Read to at Least Three Times per Week Read to Fewer than Three Times per Week Started Reading by age 4 33 60 Started Reading after age 4 58 17 Lower endpoint upper endpoint
Suppose we know that a confidence interval for a population proportion is (0.105,0.355), with a sample proportion of p̂=0.23. What is the margin of error?
One company recently conducted a survey in which 420 women and 420 men were asked "Are you satisfied with the work of the Minister of Health?". Of these, 155 men and 118 women said they were satisfied with the minister's work. Assume that the experimental design was correct. Questions 1 and 2 cover this survey. 1. Find the upper limit of 95% confidence interval for the difference in the proportion of men and women who are happy with the work of the Minister (let men be group 1). 1. 0.03. 2. 0.09. 3. 0.15. 4. It is not possible to apply a normal approach and therefore we can not calculate the confidence interval. 2. What is the rejection area if it is to be examined whether the proportion of men and women who are satisfied with the job of Prime Minister is different (use a = 0.05)? 1. RejectHO efz 1.96. 2. Reject HO if z> 1.64. 3. RejectHO efz> -1.96 or <1.96. 4. Insufficient information provided to answer this.
2. You are going to construct a 90% confidence interval for the proportion ofadults that have a post-secondary education. You want the margin of errorto be .03. Your initial guess is that 35% of the population has a postsecondary education. What should the sample size be to achieve thismargin of error?
If all the confidence intervals overlapped, does that imply that the mean must be in that overlap? I claim 49.5% of the study population is female. Conduct a hypothesis to test if I am wrong, to see if the population proportion is of female patients is not 49.5%. Use a 5% level of significance. State your conclusion to each hypothesis test. What is a Type I error? How many of your hypothesis tests agree? If different samples gave you different hypothesis test results (i.e. some rejected the null hypothesis and some did not) does that mean your sampling design for the incorrect hypothesis test(s) was faulty?
In order to compare the means of two populations, independent random samples of 410 observations are selected from each population, with the results found in the table to the right. Complete parts a through e below. BOCO Sample 1 x₁ = 5,260 $₁=155 Sample 2 X₂=5,232 $2=200 a. Use a 95% confidence interval to estimate the difference between the population means (H₁-H2)- Interpret the confidence interval The confidence interval is (0) (Round to one decimal place as needed.)
I'm having trouble trying to figure out how to work the problem below out. Let’s say that 44 percent of the 1,300 U.S. adults who responded to a poll about marijuana legalization said they support legalization. Let’s also say the margin of error for the results is +/- 3 percentage points. The margin of error tells us there’s a high probability that nationwide support for marijuana legalization falls: The correct interpretation of this confidence interval is:
Determine whether the following statements are True or False: In a confidence interval (CI) for a population mean, the margin of error (MOE) is half the width of the CI. If we constructed 1000 independent 90% CI’s for a population mean µ, thenwe’d expect about 900 of them to contain µ If we increase the sample size of SRS’s, then the width of the CI’s corresponding to the SRS’s decreases, i.e., the CI’s become narrower
Next question If a sample proportion is 0.68, which of the following could be a 90% confidence interval for the population proportion? ..... Select all that apply. A. Lower bound: 0.59; Upper bound: 0.77 B. Lower bound: 0.66; Upper bound: 0.70 OC. Lower bound: 0.50; Upper bound: 0.77 D. Lower bound: 0.77; Upper bound: 0.95 E. Lower bound: 0.67; Upper bound: 0.71 F3 F4 F5 F7 F8 24 4. %23 2 3. 6. Left control option command
QUESTION 1 A company claims that the mean weight of coffee in its 16-ounce bags is 16.05 ounces. Consumer advocates group constructed the following 95% confidence interval (16.09, 16.12). Based on this interval, do you think that the company's claim is plausible at the 5% significance level? 16.05 lies in the interval (16.09, 16.12), so we do not reject the manufacturer's claim. 16.05 does not lie in the interval (16.0, 16.2), so we reject the manufacturer's claim. Not enough information to answer the question. 16.05 does not lie in the interval (16.09, 16.12), so we reject the company's claim.

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