Which is the product of the series of reactions? О к кон CH3CH₂CH О кон- Н Н OH Изот НСIН2О Rh/H₂ heat си, спа Eon +

Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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**Chemical Reaction and Product Identification Tutorial**

In this exercise, we're looking to identify the product of a given series of chemical reactions. 

**Reaction Sequence:**
1. **Starting Material:** CH₃CH₂CH=C=O 
2. **Reagent 1:** KOH
   - Deprotonation occurs here, resulting in the formation of potassium salt (CH₃CH₂C=OK).
3. **Reagent 2:** HCl/H₂O with heat
   - This step involves hydrolysis and results in the formation of a carboxylic acid.
4. **Reagent 3:** Rh/H₂ (Rhodium Catalyst with Hydrogen)
   - Hydrogenation results in the addition of hydrogen atoms to bonds, typically reducing double bonds to single bonds.

**Explanation of the Annotated Reagents and Products:**
In the image, annotations point to the following intermediates and products:
- The starting material CH₃CH₂CH=C=O is reacted with KOH to create a potassium salt.
- When HCl and H₂O are applied with heat, this intermediate is converted to a carboxylic acid.
- Rhodium and Hydrogen then act to reduce the carboxylic acid or other intermediates formed.

**Product Options (Compound Structures):**

1. **Option 1:**
   - Structure with a ketone group (C=O) at the second carbon.
   - Linear backbone: CH₃-CH₂-CH₂-COH.
   
2. **Option 2:**
   - Structure ending in a primary alcohol (CH₂OH).
   - Extended chain: CH₃-CH₂-CH₂-CH₂-CH₂OH.

3. **Option 3:**
   - Structure has a carbonyl group (C=O) with two methyl branches.  
   - Isoform chain: 2-Methyl-3-pentanone.

4. **Option 4:**
   - Structure with an alcohol directly attached to a triple chain backbone.
   - Extended form: 3-Methyl-2-pentanol.

By considering the reaction sequence and chemical transformations, carefully identify which structure aligns with the expected final product after all the reactions are completed.
Transcribed Image Text:**Chemical Reaction and Product Identification Tutorial** In this exercise, we're looking to identify the product of a given series of chemical reactions. **Reaction Sequence:** 1. **Starting Material:** CH₃CH₂CH=C=O 2. **Reagent 1:** KOH - Deprotonation occurs here, resulting in the formation of potassium salt (CH₃CH₂C=OK). 3. **Reagent 2:** HCl/H₂O with heat - This step involves hydrolysis and results in the formation of a carboxylic acid. 4. **Reagent 3:** Rh/H₂ (Rhodium Catalyst with Hydrogen) - Hydrogenation results in the addition of hydrogen atoms to bonds, typically reducing double bonds to single bonds. **Explanation of the Annotated Reagents and Products:** In the image, annotations point to the following intermediates and products: - The starting material CH₃CH₂CH=C=O is reacted with KOH to create a potassium salt. - When HCl and H₂O are applied with heat, this intermediate is converted to a carboxylic acid. - Rhodium and Hydrogen then act to reduce the carboxylic acid or other intermediates formed. **Product Options (Compound Structures):** 1. **Option 1:** - Structure with a ketone group (C=O) at the second carbon. - Linear backbone: CH₃-CH₂-CH₂-COH. 2. **Option 2:** - Structure ending in a primary alcohol (CH₂OH). - Extended chain: CH₃-CH₂-CH₂-CH₂-CH₂OH. 3. **Option 3:** - Structure has a carbonyl group (C=O) with two methyl branches. - Isoform chain: 2-Methyl-3-pentanone. 4. **Option 4:** - Structure with an alcohol directly attached to a triple chain backbone. - Extended form: 3-Methyl-2-pentanol. By considering the reaction sequence and chemical transformations, carefully identify which structure aligns with the expected final product after all the reactions are completed.
**Question:**
Which is the main product from the reaction of (S)-2-methylpentanal with an aqueous base?

**Options:**
1. \[(S)-2-methylpentanal\]

   - Structure: 
   ![chair image](https://www.static-uploader.com/upload/96i71mt5c7e6i7/2023-10-08/2638613-chair.png)

2. \[(E)-2-methylpent-2-en-1-ol\]

   - Structure: 
   ![chair image](https://www.static-uploader.com/upload/96i71mt5c7e6i7/2023-10-08/2638613-chair.png)

3. \[racemic-2-methylpentanal\]

   - Structure: 
   ![chair image](https://www.static-uploader.com/upload/96i71mt5c7e6i7/2023-10-08/2638613-chair.png)

4. \[(R)-2-methylpentanal\]

   - Structure: 
   ![chair image](https://www.static-uploader.com/upload/96i71mt5c7e6i7/2023-10-08/2638613-chair.png)

5. \[(E)-2-methylpent-1-en-1-ol\]

   - Structure: 
   ![chair image](https://www.static-uploader.com/upload/96i71mt5c7e6i7/2023-10-08/2638613-chair.png)

**Solution:**
The main product from the reaction of \[(S)-2-methylpentanal\] with aqueous NaOH in ethanol is \[(E)-2-methylpent-2-en-1-ol\].

In the provided image, each option is accompanied by a structure diagram representing the corresponding chemical compound. The correct answer, as indicated by the red circle mark in the image, is option 2:
\[(E)-2-methylpent-2-en-1-ol\]. This is the primary product formed due to the reaction conditions specified (aqueous NaOH and ethanol), which typically lead to the formation of an enolate and subsequent aldol condensation.
Transcribed Image Text:**Question:** Which is the main product from the reaction of (S)-2-methylpentanal with an aqueous base? **Options:** 1. \[(S)-2-methylpentanal\] - Structure: ![chair image](https://www.static-uploader.com/upload/96i71mt5c7e6i7/2023-10-08/2638613-chair.png) 2. \[(E)-2-methylpent-2-en-1-ol\] - Structure: ![chair image](https://www.static-uploader.com/upload/96i71mt5c7e6i7/2023-10-08/2638613-chair.png) 3. \[racemic-2-methylpentanal\] - Structure: ![chair image](https://www.static-uploader.com/upload/96i71mt5c7e6i7/2023-10-08/2638613-chair.png) 4. \[(R)-2-methylpentanal\] - Structure: ![chair image](https://www.static-uploader.com/upload/96i71mt5c7e6i7/2023-10-08/2638613-chair.png) 5. \[(E)-2-methylpent-1-en-1-ol\] - Structure: ![chair image](https://www.static-uploader.com/upload/96i71mt5c7e6i7/2023-10-08/2638613-chair.png) **Solution:** The main product from the reaction of \[(S)-2-methylpentanal\] with aqueous NaOH in ethanol is \[(E)-2-methylpent-2-en-1-ol\]. In the provided image, each option is accompanied by a structure diagram representing the corresponding chemical compound. The correct answer, as indicated by the red circle mark in the image, is option 2: \[(E)-2-methylpent-2-en-1-ol\]. This is the primary product formed due to the reaction conditions specified (aqueous NaOH and ethanol), which typically lead to the formation of an enolate and subsequent aldol condensation.
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