Which intermolecular forces are present in a pure sample of the compound below? O dipole-dipole and London-dispersion forces O hydrogen-bonding and dipole-dipole forces O hydrogen-bonding, dipole-dipole, and hydrogen bonding O London-dispersion forces and hydrogen bonding

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Chapter1: Chemical Foundations
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**Question 8:**

**Which intermolecular forces are present in a pure sample of the compound below?**

![Chemical Structure](image_url) [Here is a depiction of the compound, which is shown as a V-shaped skeletal formula, representing a molecule with a chain of three carbon atoms, where the middle carbon is bonded to one hydrogen and the two terminal carbons are bonded to three hydrogens each.]

- O  dipole-dipole and London-dispersion forces
- O  hydrogen-bonding and dipole-dipole forces
- O  hydrogen-bonding, dipole-dipole, and hydrogen bonding
- O  London-dispersion forces and hydrogen bonding

**Explanation:**
The skeletal formula provided suggests that the compound is a simple hydrocarbon, specifically propane (C3H8). Hydrocarbons like propane are nonpolar molecules, thus the predominant intermolecular force present in a pure sample of propane would be London-dispersion forces, also known as Van der Waals forces, due to the momentary dipoles created in the electron cloud.

**Correct Answer:** O London-dispersion forces and hydrogen bonding (note that the answer might contain a mistake; ideally, it should only list London-dispersion forces for non-polar molecules like propane).

**Graphs/Diagrams Explanation:**
There are no graphs present in this question. The skeletal diagram is a line representation of a hydrocarbon, where each vertex (corner) represents a carbon atom and the lines (edges) represent bonds between the carbon atoms. This simplified representation helps in identifying the type of molecule and the nature of intermolecular forces without focusing on the full structural formula.
Transcribed Image Text:**Question 8:** **Which intermolecular forces are present in a pure sample of the compound below?** ![Chemical Structure](image_url) [Here is a depiction of the compound, which is shown as a V-shaped skeletal formula, representing a molecule with a chain of three carbon atoms, where the middle carbon is bonded to one hydrogen and the two terminal carbons are bonded to three hydrogens each.] - O dipole-dipole and London-dispersion forces - O hydrogen-bonding and dipole-dipole forces - O hydrogen-bonding, dipole-dipole, and hydrogen bonding - O London-dispersion forces and hydrogen bonding **Explanation:** The skeletal formula provided suggests that the compound is a simple hydrocarbon, specifically propane (C3H8). Hydrocarbons like propane are nonpolar molecules, thus the predominant intermolecular force present in a pure sample of propane would be London-dispersion forces, also known as Van der Waals forces, due to the momentary dipoles created in the electron cloud. **Correct Answer:** O London-dispersion forces and hydrogen bonding (note that the answer might contain a mistake; ideally, it should only list London-dispersion forces for non-polar molecules like propane). **Graphs/Diagrams Explanation:** There are no graphs present in this question. The skeletal diagram is a line representation of a hydrocarbon, where each vertex (corner) represents a carbon atom and the lines (edges) represent bonds between the carbon atoms. This simplified representation helps in identifying the type of molecule and the nature of intermolecular forces without focusing on the full structural formula.
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