Which hydrogen is removed by base in this elimination reaction? На. На На о нь Hc Hd Hb Ha Br He C Hd Hc Hd Hd

Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Question:**

Which hydrogen is removed by base in this elimination reaction?

**Diagram Explanation:**

The left side of the diagram shows a molecular structure with the following labels:
- Two carbon atoms are connected by a single bond.
- The first carbon (left) has bonds to two hydrogen atoms labeled "Ha" and one bond to another "Ha".
- The second carbon (middle) is bonded to a bromine atom and a hydrogen labeled "Hb".
- The central carbon (right) is bonded to two hydrogens labeled "Hc".
- The final carbon (furthest right) is bonded to three hydrogens labeled "Hd".

The right side of the diagram shows the resulting alkene with a double bond between the middle two carbon atoms.

**Options:**

- ⭕ Ha
- ⭕ Hb
- ⭕ Hc
- ⭕ Hd

**Answer Explanation:**

This is a typical elimination (E2) reaction where a base removes a hydrogen adjacent to a leaving group (in this case, Br) to form a double bond. The hydrogen removed is typically anti-periplanar to the leaving group.
Transcribed Image Text:**Question:** Which hydrogen is removed by base in this elimination reaction? **Diagram Explanation:** The left side of the diagram shows a molecular structure with the following labels: - Two carbon atoms are connected by a single bond. - The first carbon (left) has bonds to two hydrogen atoms labeled "Ha" and one bond to another "Ha". - The second carbon (middle) is bonded to a bromine atom and a hydrogen labeled "Hb". - The central carbon (right) is bonded to two hydrogens labeled "Hc". - The final carbon (furthest right) is bonded to three hydrogens labeled "Hd". The right side of the diagram shows the resulting alkene with a double bond between the middle two carbon atoms. **Options:** - ⭕ Ha - ⭕ Hb - ⭕ Hc - ⭕ Hd **Answer Explanation:** This is a typical elimination (E2) reaction where a base removes a hydrogen adjacent to a leaving group (in this case, Br) to form a double bond. The hydrogen removed is typically anti-periplanar to the leaving group.
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