Which distribution would be used to find the multiplier for this confidenceinterval?Select one:а.t-distribution with df = 250 + 400 - 2%3Db. standard normal distributionС.t-distribution with df = 399 A random sample of upperclassmen (juniors, seniors) and a random sample oflowerclassmen (freshman, sophomores) were asked if they use study groups forany of their classes. 157 (63%) out of 250 upperclassmen and 232 (58%) out of400 lowerclassmen reported using study groups. Suppose all the assumptionsfor conducting the hypothesis test are met.

Answered: Which distribution would be used to…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The length of a fully grown hibiscus plant has a mean 35cm. It is found that 5% of these plants are longer than 45cm. One of the steps to finding the standard deviation σ is P (Z < 1.645)=0.95 Explain how the standard normal distribution table was used to arrive at this 1.645 figure in one of the steps.
Cell Phone Lifetimes A recent study of the lifetimes of cell phones found the average is 23.2 months. The standard deviation is 3.1 months. If a company provides its 33 employees with a cell phone, find the probability that the mean lifetime of these phones will be less than 23.8 months. Assume cell phone life is a normally distributed variable, the sample is taken from a large population, and the correction factor can be ignored. Use a TI-83 Plus/TI-84 Plus calculator. Round your answer to at least four decimal places. P(X<23.8)=
The length of time it takes to find a parking space at the local grocery store, follows a normal distribution with a mean of 5 min and a standard deviation of 2 min. Find the 70th percentile for the time looking for a parking space.
a random sample of n = 36 students who registered for Introductory Psychology is placed in the online version of the course. At the end of the semester, all students take the same final exam. The average score for the sample is M = 76. For the general population of students taking the traditional lecture class, the final exam scores form a normal distribution with a mean of u = 71. a. If the final exam scores for the population have a standard deviation of o = 12, does the sample provide enough evidence to conclude that the new online course is significantly different from the tra- ditional class? Use a two-tailed test with a = .05. %3D b. If the population standard deviation is o = 18, is the sample sufficient to demonstrate a significant differ- ence? Again, use a two-tailed test with a = ,05. c. Comparing your answers for parts a and b, explain how the magnitude of the standard deviation influ- ences the outcome of a hypothesis test.
An investigator polls a representative sample of common cold sufferers, asking them to estimate the number of hours of physical discomfort caused by their most recent cold. Their estimates approximate a normal curve with a mean of 91 hours and a standard deviation of 23 hours. Show your z-score and p-value calculations. Inverse Normal Distribution: What is the estimated number of hours for the shortest-suffering 20 percent? Inverse Normal Distribution: A medical researcher wishes to concentrate on the 10 percent who suffered the most. To be included in this group, a patient would have suffered how many hours?
The discharge of suspended solids from a phosphate mine is normally distributed, with a mean daily discharge of 27 milligrams per liter (mg/l) and a standard deviation of 14 mg/L. What proportion of days will the daily discharge exceed 50 mg/L?
A medical company pack medication in bags marked as 250 gA large number of packs of medication were weighed and the mean and standard deviation were calculated as 255 g and 2.5 g respectively.Assuming this data is normally distributed, what percentage of packs are underweight? Develop a Standard Normal Distribution curve.
Cell Phone Lifetimes A recent study of the lifetimes of cell phones found the average is 23.8 months. The standard deviation is 5.8 months. If a company provides its 33 employees with a cell phone, find the probability that the mean lifetime of these phones will be less than 23.8 months. Assume cell phone life is a normally distributed variable, the sample is taken from a large population, and the correction factor can be ignored. Use a TI-83 Plus/TI-84 Plus calculator. Round your answer to at least four decimal places. <PX23.8)=
The standard normal curve exhibits heavier tails versus the t-distribution curve True False

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Which distribution would be used to find the multiplier for this confidence interval? Select one: a. t-distribution with df = 250 + 400 - 2 b. standard normal distribution С. t-distribution with df = 399