Which chi-square distribution would be closest to a normal distribution? Multiple Choice
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Which chi-square distribution would be closest to a
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The distribution with 3 degrees of freedom
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The distribution with 12 degrees of freedom
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The distribution with 15 degrees of freedom
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The distribution with 9 degrees of freedom
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- Select the appropriate word or phrase to complete each sentence. Part: 0/2 Part 1 of 2 The proportion of a population that is contained within an interval corresponds to an area under the probability normal curve. Part: 1/2 Part 2 of 2 v each other. a normal distribution are (Choose one) standardized by equal to different from The mean, median, and mode Continue OEmersonOnly b and c5 Use the table below to find the percentage of data items in a normal distribution that lie a. below and b. above a z-score of −2.1. z-score -3.0 -2.9 -2.8 -2.7 -2.6 -2.5 -2.4 -2.3 -2.2 -2.1 Percentile 0.13 0.19 0.26 0.35 0.47 0.62 0.82 1.07 1.39 1.79 z-score -2.0 -1.9 -1.8 -1.7 -1.6 -1.5 -1.4 -1.3 -1.2 -1.1 Percentile 2.28 2.87 3.59 4.46 5.48 6.68 8.08 9.68 11.51 13.57 z-score -1.0 -0.9 -0.8 -0.7 -0.6 -0.5 -0.4 -0.3 -0.2 -0.1 Percentile 15.87 18.41 21.19 24.20 27.43 30.85 34.46 38.21 42.07 46.02 a. The percentage of data items that lie below the z-score is ___%. b. The percentage of data items that lie above the z-score is ___%
- Plz urgentlyF4need help pleaseResources Giye Up? The number of flaws per square yard in a type of carpet material varies with mean 1.6 flaws per square yard and standard deviation 1.2 flaws per square yard. Without doing any calculations, explain why you cannot use a Normal distribution to calculate the probability of randomly selecting a 1 square yard of material and finding 2 or more flaws. O You cannot use a Normal distribution to calculate the probability of randomly selecting a 1 square yard of material and finding 2 or more flaws because it is impossible for carpet to have 1.6 flaws. You cannot use a Normal distribution to calculate the probability of randomly selecting a1 square yard of material and finding 2 or more flaws because the population distribution is not Normal and the sample size is not at least 30. You cannot use a Normal distribution because the Normal distribution only applies to proportions. You cannot use a Normal distribution to calculate the probability of randomly selecting a 1 square…
- Find the z-scores that separates the middle 85 % of the distribution from the area in the tail of the standard normal distribution.First z-score = [ Note: If it did not work, try switching your answer around]Second z-score =Website 1 A market analyst wants to know if the new website he designed is showing increased page views per visit and calculates the summary statistics in the table to the right. Assume that the new website is website 1 and the old website is website 2. Test the hypothesis that the mean number of page views from the two websites is the same. You may assume that the number of page views from each website follaw a Normal distribution. Complete parts a through e below. Website 2 n, =90 y, =6.7 = 95 =63 55 -5.6 t-0.490 a) Calculato the Pvalun of the statiatic given that the approximation formula gives df = 182.6. The Pvalue is (Round to three decimai places as needed.) b) Caloulate the P-value of the statistic using the rule that df minin, - 1, n-1) The Pvalue is (Round to three decimal places as needed.) e) What do you conclude at a=0,107 H, for both cases. There sufficient evidence to reject the caim that the mean number of page visits is the same for the two websites, in favor of the…Plzz explain
- Anticipated consumer demand in a restaurant for free range steaks next month can be modeled by a normal random variable with mean 1,300 pounds and standard deviation 90 pounds. a. What is the probability that demand will exceed 1,100 pounds? b. What is the probability that demand will be between 1,200 and 1,400 pounds? c. The probability is 0.10 that demand will be more than how many pounds? i Standard Normal Distribution Table Click the icon to view the standard normal table of the cumulative distribution function. a. The probability that demand will exceed 1,100 pounds is 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09 z (Round to four decimal places as needed.) 0.0 0.5000 0.5040 0.5080 0.5120 0.5160 0.5199 0.5239 0.5279 0.5319 0.5359 0.1 0.5398 0.5438 0.5478 0.5517 0.5557 0.5596 0.5636 0.5675 0.5714 0.5753 0.2 0.5793 0.5832 0.5871 0.5910 0.5948 0.5987 0.6026 0.6064 0.6103 0.6141 0.3 0.6179 0.6217 0.6255 0.6293 0.6331 0.6368 0.6406 0.6443 0.6480 0.6517 0.4 0.6554 0.6591 0.6628 0.6664…00 %24 In the Standard Normal Distribution, what is the probability of getting a z-score between -.54 and 1.68? Write both your answer and your Excel formula here. ovi ima pod ovie ...-4 ovie unɔod ts 150 132 OCT 25 tv MacBook Pro esc # & $ % 2 4. 8. R caps lock HA binomial experiment is given. Decide whether you can use the normal distribution to approximate the binomial distribution. If you can, find the mean and standard deviation. If you cannot, explain why. A survey of adults found that 44% have used a multivitamin in the past 12 months. You randomly select 50 adults and ask them if they have used a multivitamin in the past 12 months.
