recent 10k run, the finishers are normally distributed with mean 58 minutes and standard deviation 12 minutes. Complete parts (a) through (d) bell here to view page 1 of the standard normal distribution table. here to view page 2 of the standard normal distribution table. termine the percentage of finishers with times between 45 and 70 minutes. oximately 70.12 % of finishers had times between 45 and 70 minutes. and to two decimal places as needed.) etermine the percentage of finishers with times less than 75 minutes. roximately 92.17% of finishers had times less than 75 minutes. und to two decimal places as needed.) btain and interpret the 30th percentile for the finishing times. 30th percentile is 51.71 minutes. und to two decimal places as needed.) rpret the 30th percentile. Select the correct choice below and fill in the answer box(es) to complete your choice. me integers or decimals rounded to two decimal places as needed.) A. This percentile means that % of the finishing times are less than B. This percentile is the value that is % greater than the smallest finishing time. C. This percentile means that % of the finishing times are equal to D. This percentile is the value that is % less than the average finishing time.

MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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For a recent 10k run, the finishers are normally distributed with mean 58 minutes and standard deviation 12 minutes. Complete parts (a) through (d) below.
Click here to view page 1 of the standard normal distribution table.
Click here to view page 2 of the standard normal distribution table.
a. Determine the percentage of finishers with times between 45 and 70 minutes.
Approximately 70.12 % of finishers had times between 45 and 70 minutes.
(Round to two decimal places as needed.)
b. Determine the percentage of finishers with times less than 75 minutes.
Approximately 92.17 % of finishers had times less than 75 minutes.
(Round to two decimal places as needed.)
c. Obtain and interpret the 30th percentile for the finishing times.
The 30th percentile is 51.71 minutes.
(Round to two decimal places as needed.)
Interpret the 30th percentile. Select the correct choice below and fill in the answer box(es) to complete your choice.
(Type integers or decimals rounded to two decimal places as needed.)
OA. This percentile means that % of the finishing times are less than
OB. This percentile is the value that is % greater than the smallest finishing time..
OC. This percentile means that % of the finishing times are equal to
OD. This percentile is the value that is
% less than the average finishing time.
Transcribed Image Text:T ↑ For a recent 10k run, the finishers are normally distributed with mean 58 minutes and standard deviation 12 minutes. Complete parts (a) through (d) below. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. a. Determine the percentage of finishers with times between 45 and 70 minutes. Approximately 70.12 % of finishers had times between 45 and 70 minutes. (Round to two decimal places as needed.) b. Determine the percentage of finishers with times less than 75 minutes. Approximately 92.17 % of finishers had times less than 75 minutes. (Round to two decimal places as needed.) c. Obtain and interpret the 30th percentile for the finishing times. The 30th percentile is 51.71 minutes. (Round to two decimal places as needed.) Interpret the 30th percentile. Select the correct choice below and fill in the answer box(es) to complete your choice. (Type integers or decimals rounded to two decimal places as needed.) OA. This percentile means that % of the finishing times are less than OB. This percentile is the value that is % greater than the smallest finishing time.. OC. This percentile means that % of the finishing times are equal to OD. This percentile is the value that is % less than the average finishing time.
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