which block completes the code to generate 'Remainder: 0.0' as output?(replacing the XXX)using: def Remainder(a, b): if b == 0: return(b % a) else: return(a % b)XXXfinally: print('Remainder:', z) z = Remainder(a, b)try:a = 0b = 0except:print('Wrong value entered')try:a = 20b = 0z = Remainder(a, b)except:print('Wrong value entered')a = 10b = 10z = Remainder(a, b)except:print('Wrong value entered')

'''First lets analyze the given code with each option'''def Remainder(a, b):#funciton takes, a,b as arguments if b == 0:#if b is 0 return(b % a)#then returns b%a else:#if b is not 0 return(a % b)#then return a%b#now by using option1z= Remainder(a,b)#calling function by a,b#but a,b are defined, so , this gives error#hence it is not correct optiontry: a=0 b=0except: print('Wrong value entered')finally: print('Remainder:', z) #now by using option 2 def Remainder(a, b):#funciton takes, a,b as arguments if b == 0:#if b is 0 return(b % a)#then returns b%a else:#if b is not 0 return(a % b)#then return a%btry:#starting try block#declaring a,b a=20 b=0 #calling method by passing a,b z = Remainder(a,b)#since b is 0 #method returns b%a :0%20 = 0 #so z value is 0except:#since try block dont have any errors, this will not be executed print('Wrong value entered')finally:#this will be executed print('Remainder:', z)#it prints Remainder: 0 #which is our desired output #now by using option 3 def Remainder(a, b):#funciton takes, a,b as arguments if b == 0:#if b is 0 return(b % a)#then returns b%a else:#if b is not 0 return(a % b)#then return a%b #declaring a,ba=10 b=10#unnecessary indent causes error z = Remainder(a,b)except:#except used with try, causes error print('Wrong value entered')finally: print('Remainder:', z) so,Answer is: try: a=20 b=0 z = Remainder(a,b)except: print('Wrong value entered')