Which are true about p-nitroacetophenone and p-methoxyacetophenone? Select the correct response(s): p-methoxyacetophenone is less reactive because it has a deactivating substituent. p-methoxyacetophenone is more reactive because it has an activating substituent. the carbonyl carbon is more electrophilic in p-nitroacetophenone the carbonyl carbon is more electrophilic in p-methoxyacetophenone the carbonyl carbon is more nucleophilic in p-nitroacetophenone p-nitroacetophenone is more reactive because it has an activating substituent. p-nitroacetophenone is less reactive because it has a deactivating substituent. 0

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Which are true about p-nitroacetophenone and p-methoxyacetophenone?
Select the correct response(s):
p-methoxyacetophenone is less reactive because it has a deactivating substituent.
p-methoxyacetophenone is more reactive because it has an activating substituent.
the carbonyl carbon is more electrophilic in p-nitroacetophenone
the carbonyl carbon is more electrophilic in p-methoxyacetophenone
the carbonyl carbon is more nucleophilic in p-nitroacetophenone
p-nitroacetophenone is more reactive because it has an activating substituent.
p-nitroacetophenone is less reactive because it has a deactivating substituent.
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Transcribed Image Text:Which are true about p-nitroacetophenone and p-methoxyacetophenone? Select the correct response(s): p-methoxyacetophenone is less reactive because it has a deactivating substituent. p-methoxyacetophenone is more reactive because it has an activating substituent. the carbonyl carbon is more electrophilic in p-nitroacetophenone the carbonyl carbon is more electrophilic in p-methoxyacetophenone the carbonyl carbon is more nucleophilic in p-nitroacetophenone p-nitroacetophenone is more reactive because it has an activating substituent. p-nitroacetophenone is less reactive because it has a deactivating substituent. 0 0
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