Where segments ad & bc are the processes and segment ab & cd are the processes; and the volumes involved are Va, Vb, Vc, Vd, and the two temperatures TC and Sol. Since AU = 0, then the heat on segment ab is QH = TH In | The heat on segment cd is QC = - TC In By inspection, we can say that THV-1 and TH Y-1. Thus, vb then |QC/QH| = Which solves the efficiency of the Carnot engine.
Where segments ad & bc are the processes and segment ab & cd are the processes; and the volumes involved are Va, Vb, Vc, Vd, and the two temperatures TC and Sol. Since AU = 0, then the heat on segment ab is QH = TH In | The heat on segment cd is QC = - TC In By inspection, we can say that THV-1 and TH Y-1. Thus, vb then |QC/QH| = Which solves the efficiency of the Carnot engine.
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Question
Calculate the efficiency of the Carnot Engine for ideal gas. Consider the figure below for a complete cycle of Carnot engine, where the cycle goes from ad->ab->bc->cd

Transcribed Image Text:Where segments ad & bc are the
processes and segment ab & cd are the
processes;
and the volumes involved are Va, Vb, Vc, Vd, and the two temperatures TC and
Sol.
Since AU = 0, then the heat on segment ab is
QH =
TH In |
The heat on segment cd is
QC= -
TC In
By inspection, we can say that
THV-
VY-1
H'b
and
TH
Y-1
Thus,
Vb/
then
|QC/QH| =
Which solves the efficiency of the Carnot engine.

Transcribed Image Text:Carnot cycle
Он
TH
-Tc
d
O 2016 Pearson Education, Inc.
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