What is the equilibrium constant for the following redox reaction? Cu2+ + 2Li Cu + 2Lit Litte Cu²+ + 2e 6.52 X 10² -> Li EO = - 3.04 V Cu EO= 1.94 x 1057 3.26 x 105 3.77 × 10114 1.14 × 102 = + 0.34 V
What is the equilibrium constant for the following redox reaction? Cu2+ + 2Li Cu + 2Lit Litte Cu²+ + 2e 6.52 X 10² -> Li EO = - 3.04 V Cu EO= 1.94 x 1057 3.26 x 105 3.77 × 10114 1.14 × 102 = + 0.34 V
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![What is the equilibrium constant for the following redox reaction?
Cu2+ + 2Li
Cu + 2Lit
Litte
Cu²+ + 2e
6.52 X
-> Li EO = - 3.04 V
Cu EO=
10²
1.94 x 1057
3.77 x
3.26 × 105
10114
1.14 x 10²
= + 0.34 V](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbfdec7a9-854b-4b3c-a428-27291103e6b1%2F9a8c3716-85c6-4881-ab27-393568f4afe7%2Fuhiodog_processed.jpeg&w=3840&q=75)
Transcribed Image Text:What is the equilibrium constant for the following redox reaction?
Cu2+ + 2Li
Cu + 2Lit
Litte
Cu²+ + 2e
6.52 X
-> Li EO = - 3.04 V
Cu EO=
10²
1.94 x 1057
3.77 x
3.26 × 105
10114
1.14 x 10²
= + 0.34 V
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Where does the 3.77 come from, if you don't mind me asking?
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