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- Sham Treatment 5. Researchers conducted a study to determine whether magnets are effective in treating back pain. The results are shown in the table for the treatment (with magnets) group and the sham (or placebo) group. The results are a measure of reduction in back pain. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. 27 n 27 0.42 0.47 1.38 0.95 a. Use a 0.05 significance level to test the claim that those treated with magnets have a greater mean reduction in pa than those given a sham treatment. What are the null and alternative hypotheses? O A. Ho: H1 H2 The test statistic, t, is (Round to two decimal places as needed.) The P-value is (Round to three decimal places as needed.) State the conclusion for the test. the null hypothesis. There (2). sufficient evidence to support the claim that those (1). treated with…The dependent is variance inflation factor, make a decision whether it need to drop any variables.1.3 answer in 2 decimal places No need solutions
- 5.STATISTICAL INFERENCECompute mean, variance, and standard deviationFresh Mart QQ's profit on each delivery is estimated by RM P, where the random variable P has mean u and variance 1.92. According to previous record, the value of u used to be 0.85. Manager suspects that this value has increased. In order to test at the 5% significance level whether the value of u has increased, a random sample of 50 delivery transaction is chosen. Assume the variance of P is unchanged. Given that Ep 59. Find the unbiased estimates of the population mean. Stating the null and alternative hypotheses, test at 5% significance level on whether the manager's suspicion is true. The alternative hypothesis for a test is stated as below: H:µ # 30 State the null hypothesis and determine whether this test is one-tail test or two- tail test hypothesis.
- Let X-1: correct, X=0 : wrong And P= Pr(X=1)=2/5 What is the variance? .32 O.6 O .4Can you please help me with parts C, E, and F?Q1.2 Mean of X A medical practice collects data on its patients with respect to several personal habits. The following table gives the distribution of the number of alcoholic drinks consumed per day in that population of patients. X = # of drinks per day Probability Save Answer Q1.3 Variance of X X = # of drinks per day Probability 0 0.38 Find the mean for this random variable, that is find ux. Show your work in the space below. Save Answer A medical practice collects data on its patients with respect to several personal habits. The following table gives the distribution of the number of alcoholic drinks consumed per day in that population of patients. 0 0.38 Q1.4 Standard Deviation of X X = # of drinks per day Probability 1 0.32 0 0.38 1 0.32 2 0.25 Find the variance for this random variable, that is find (ox)². Only show the first and last term of the work required. 1 2 0.25 A medical practice collects data on its patients with respect to several personal habits. The following table…
- Using the unemployment data provided, investigate the association between the male unemployment rate in 2007 and 2010 for a sample of 52 countries. Complete parts (a) through (4). m Click the icon to view the data table. OC The plot of the residuals against x tends to cluster as x increases, which is a possible violation of the Linearity Conditon. The Normal probability plot indicates that the Normal Population Assumption is satisfied. OD. The plot of the residuals againat x shows no patten, which satisfes the conditions for linear regression. The Normal probability plot indicates that the Nomal Probability Assumption is violated. c) Test an appropriate hypothesis using a- 0,05 to determine it the association is signiftcant. Choose the corect nul and altemative hypotheses. OA Ha: 0 OB. Ho: lo " 0 HA P0 or l 0 O C. Ho Po-0 OD. Ho: la =P HA PoLet X have beta distribution with a = 2 and B = 3. Then the mean and the variance of X, respectively, are Select one: O a. 0.04 and 0.4 O b. 0.02 and 0.04 O c. 0.4 and 0.04 O d. 0.4 and 0.20Solve this problem given in picture.