When writing the original expression in terms of simpler logarithmic expressions, an error was made. Where did this error occur? (1) loga () (2) = loga (3x) – loga(y'z) (3) = loga (3x)-[logaly") +loga(z°)] (4) = log, (3x)-4 logaly)-5loga(2) (5) = 3log. (x) - 4logaly)-5loga(2) 3x %3D %3D

When writing the original expression in terms of simpler logarithmic expressions, an error was made. Where did this error occur? (1) loga () (2) = loga (3x) – loga(y'z) (3) = loga (3x)-[logaly") +loga(z°)] (4) = log, (3x)-4 logaly)-5loga(2) (5) = 3log. (x) - 4logaly)-5loga(2) 3x %3D %3D

Calculus: Early Transcendentals

8th Edition

ISBN:9781285741550

Author:James Stewart

Publisher:James Stewart

Chapter1: Functions And Models

Section: Chapter Questions

Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...

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Question

What steps did the error occur on?

When writing the original expression in terms of simpler logarithmic
expressions, an error was made. Where did this error occur?
(1) loga ()
(2) = loga (3x) – loga(y'z")
(3) = loga (3x)-[ logaly") +loga(z°)]
(4) = loga (3x)-4logaly)-5loga(2)
(5) = 3log, ca)-4 logaly)-5loga(2)
3x
%3D

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