When we have a midterm exam of a probability course in a classroom, we often design two versions of the midterm exam paper. We do not have cameras in the classroom. In November, 2019, each version had 10 questions. Version A was the same as Version B except for two questions: in each of those two questions, two versions were different only on one number. Difference Version A Version B Question 2 P(A)30.4 Question 7 a3D0.05 P(A)-0.5 a=0.10 Student John worked on Version A, but his solutions were using the numbers of Version B. The student at John's left side and the student at John's right side had Version B. As we know well, it is possible for a pérson to make mistakes on reading numbers. According to a research report in 1950, the probability that a person had this type of mistakes in one question was less than 1%. Suppose that a person makes the mistake in different questions are independent. The probability that John did the exam by himself would be less than 0.01% from 0.012-0.01%. Hence, the instructor claimed that John cheated. However, John did not cheat. Now, John is going to appeal to the fair committee. How can John argue that he did not cheat?
When we have a midterm exam of a probability course in a classroom, we often design two versions of the midterm exam paper. We do not have cameras in the classroom. In November, 2019, each version had 10 questions. Version A was the same as Version B except for two questions: in each of those two questions, two versions were different only on one number. Difference Version A Version B Question 2 P(A)30.4 Question 7 a3D0.05 P(A)-0.5 a=0.10 Student John worked on Version A, but his solutions were using the numbers of Version B. The student at John's left side and the student at John's right side had Version B. As we know well, it is possible for a pérson to make mistakes on reading numbers. According to a research report in 1950, the probability that a person had this type of mistakes in one question was less than 1%. Suppose that a person makes the mistake in different questions are independent. The probability that John did the exam by himself would be less than 0.01% from 0.012-0.01%. Hence, the instructor claimed that John cheated. However, John did not cheat. Now, John is going to appeal to the fair committee. How can John argue that he did not cheat?
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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Contingency Table
A contingency table can be defined as the visual representation of the relationship between two or more categorical variables that can be evaluated and registered. It is a categorical version of the scatterplot, which is used to investigate the linear relationship between two variables. A contingency table is indeed a type of frequency distribution table that displays two variables at the same time.
Binomial Distribution
Binomial is an algebraic expression of the sum or the difference of two terms. Before knowing about binomial distribution, we must know about the binomial theorem.
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