Homework Help is Here – Start Your Trial Now!
Math
Probability
When we have a midterm exam of a probability course in a classroom, we often design two versions of the midterm exam paper. We do not have cameras in the classroom. In November, 2019, each version had 10 questions. Version A was the same as Version B except for two questions: in each of those two questions, two versions were different only on one number. Difference Version A Version B Question 2 P(A)30.4 Question 7 a3D0.05 P(A)-0.5 a=0.10 Student John worked on Version A, but his solutions were using the numbers of Version B. The student at John's left side and the student at John's right side had Version B. As we know well, it is possible for a pérson to make mistakes on reading numbers. According to a research report in 1950, the probability that a person had this type of mistakes in one question was less than 1%. Suppose that a person makes the mistake in different questions are independent. The probability that John did the exam by himself would be less than 0.01% from 0.012-0.01%. Hence, the instructor claimed that John cheated. However, John did not cheat. Now, John is going to appeal to the fair committee. How can John argue that he did not cheat?

When we have a midterm exam of a probability course in a classroom, we often design two versions of the midterm exam paper. We do not have cameras in the classroom. In November, 2019, each version had 10 questions. Version A was the same as Version B except for two questions: in each of those two questions, two versions were different only on one number. Difference Version A Version B Question 2 P(A)30.4 Question 7 a3D0.05 P(A)-0.5 a=0.10 Student John worked on Version A, but his solutions were using the numbers of Version B. The student at John's left side and the student at John's right side had Version B. As we know well, it is possible for a pérson to make mistakes on reading numbers. According to a research report in 1950, the probability that a person had this type of mistakes in one question was less than 1%. Suppose that a person makes the mistake in different questions are independent. The probability that John did the exam by himself would be less than 0.01% from 0.012-0.01%. Hence, the instructor claimed that John cheated. However, John did not cheat. Now, John is going to appeal to the fair committee. How can John argue that he did not cheat?

A First Course in Probability (10th Edition)
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
See similar textbooks
icon
Related questions
Topic Video
Question
When we have a midterm exam of a probability course in a classroom, we often design two versions of the midterm exam paper. We do not have cameras in the classroom. In November, 2019, each version had 10 questions. Version A was the same as Version B except for two questions: in each of those two questions, two versions were different only on one number. Difference Version A Version B Question 2 P(A)3D0.4 Question 7 a=0.05 P(A)-0.5 a=0.10 Student John worked on Version A, but his solutions were using the numbers of Version B. The student at John's left side and the student at John's right side had Version B. As we know well, it is possible for a person to make mistakes on reading numbers. According to a research report in 1950, the probability that a person had this type of mistakes in one question was less than 1%. Suppose that a person makes the mistake in different questions are independent. The probability that John did the exam by himself would be less than 0.01% from 0.012-0.01%. Hence, the instructor claimed that John cheated. However, John did not cheat. Now, John is going to appeal to the fair committee. How can John argue that he did not cheat?
Transcribed Image Text:When we have a midterm exam of a probability course in a classroom, we often design two versions of the midterm exam paper. We do not have cameras in the classroom. In November, 2019, each version had 10 questions. Version A was the same as Version B except for two questions: in each of those two questions, two versions were different only on one number. Difference Version A Version B Question 2 P(A)3D0.4 Question 7 a=0.05 P(A)-0.5 a=0.10 Student John worked on Version A, but his solutions were using the numbers of Version B. The student at John's left side and the student at John's right side had Version B. As we know well, it is possible for a person to make mistakes on reading numbers. According to a research report in 1950, the probability that a person had this type of mistakes in one question was less than 1%. Suppose that a person makes the mistake in different questions are independent. The probability that John did the exam by himself would be less than 0.01% from 0.012-0.01%. Hence, the instructor claimed that John cheated. However, John did not cheat. Now, John is going to appeal to the fair committee. How can John argue that he did not cheat?
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Knowledge Booster
Discrete Probability Distributions
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, probability and related others by exploring similar questions and additional content below.
Similar questions
Recommended textbooks for you
A First Course in Probability (10th Edition)
A First Course in Probability (10th Edition)
Probability
ISBN:
9780134753119
Author:
Sheldon Ross
Publisher:
PEARSON
A First Course in Probability
A First Course in Probability
Probability
ISBN:
9780321794772
Author:
Sheldon Ross
Publisher:
PEARSON
SEE MORE TEXTBOOKS