Could you please explain writing it out how 12C3 ends up being 220. I know how to look it up on the calculator but I need to know how to show my work by writing it out fully
Could you please explain writing it out how 12C3 ends up being 220. I know how to look it up on the calculator but I need to know how to show my work by writing it out fully
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Hi,
Could you please explain writing it out how 12C3 ends up being 220. I know how to look it up on the calculator but I need to know how to show my work by writing it out fully. Thank you.
![Answer to Problem 8TY
The probability that all three jury members are men is 0.045.
Explanation of Solution
Given info:
In a jury selection, there are 12 people in a group in which 5 peoples are men and seven are women. Also,
three members are randomly selected.
Calculation:
Combination Rule:
There are n different items and r number of selections and the selections are made without replacement,
then the number of different combinations (order does not matter counts) is given by,
n!
nCr = (n-r)!r!
The possible number of ways of choosing 3 men out of 5 men is,
Substitute 5 for 'n' and 3 for 'r', then the number of possible different treatment groups is
5!
5C3=
(5-3)13!
= 10
The number of possible ways for choosing three people is,
Substitute 5 for 'n' and 3 for 'r', then the number of possible different treatment groups is
12!
12C3 =
(12-3)13!
= 220](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa5b9ab80-c15e-46d7-8003-c733ab4df490%2F96d79497-092f-415e-8ab5-4acff0604834%2Fn42inkb_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Answer to Problem 8TY
The probability that all three jury members are men is 0.045.
Explanation of Solution
Given info:
In a jury selection, there are 12 people in a group in which 5 peoples are men and seven are women. Also,
three members are randomly selected.
Calculation:
Combination Rule:
There are n different items and r number of selections and the selections are made without replacement,
then the number of different combinations (order does not matter counts) is given by,
n!
nCr = (n-r)!r!
The possible number of ways of choosing 3 men out of 5 men is,
Substitute 5 for 'n' and 3 for 'r', then the number of possible different treatment groups is
5!
5C3=
(5-3)13!
= 10
The number of possible ways for choosing three people is,
Substitute 5 for 'n' and 3 for 'r', then the number of possible different treatment groups is
12!
12C3 =
(12-3)13!
= 220
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