### Problem StatementWhen two resistors are wired in series with a 12 V battery, the current through the battery is 0.36 A. When they are wired in parallel with the same battery, the current is 1.60 A. ### Part A**Question:** What are the values of the two resistors?**Instructions:** Express your answers in ohms and separated by a comma.**Input Field:**\[ R_1, R_2 = \_\_\_\_ \, \Omega \]**Submission Button:** - Submit**Feedback:**- Incorrect; Try Again; 4 attempts remaining**Links:**- Previous Answers- Request Answer### ExplanationIn this problem, you need to determine the values of two resistors when connected in series and parallel with a given battery. The provided information includes the voltage of the battery and the current through the circuit in each configuration.1. **Series Configuration**: - Voltage (V) = 12 V - Current (I) = 0.36 A2. **Parallel Configuration**: - Voltage (V) = 12 V - Current (I) = 1.60 AUse Ohm's Law (V = IR) to calculate the resistances systematically, considering the series and parallel arrangements.### Graphs/Diagrams There are no graphs or diagrams included in this problem.

Answered: Image /qna-images/answer/8858c497-171e-4b3a-ab9a-b1e709719b80.jpg

When two resistors are wired in series with a 12 V battery, the current through the battery is 0.36 A. When they are wired in parallel with the same battery, the current is 1.60 A. ▼ Part A What are the values of the two resistors? Express your answers in ohms and separated by a comma. 195| ΑΣΦ ? R₁, R2 = Submit Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining Provide Feedback Ω

When two resistors are wired in series with a 12 V battery, the current through the battery is 0.36 A. When they are wired in parallel with the same battery, the current is 1.60 A. ▼ Part A What are the values of the two resistors? Express your answers in ohms and separated by a comma. 195| ΑΣΦ ? R₁, R2 = Submit Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining Provide Feedback Ω

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Temperature Variance of Resistance

Electrical resistance or simply resistance is the property of a material that opposes the free flow of electrons through it. The total amount of resistance to the flow of charges (or current) is affected by many factors like the length of the conducting material, its cross-sectional area, resistivity, and temperature.

Question

### Problem Statement

When two resistors are wired in series with a 12 V battery, the current through the battery is 0.36 A. When they are wired in parallel with the same battery, the current is 1.60 A.

### Part A

**Question:**
What are the values of the two resistors?

**Instructions:**
Express your answers in ohms and separated by a comma.

**Input Field:**
\[ R_1, R_2 = \_\_\_\_ \, \Omega \]

**Submission Button:**
- Submit

**Feedback:**
- Incorrect; Try Again; 4 attempts remaining

**Links:**
- Previous Answers
- Request Answer

### Explanation

In this problem, you need to determine the values of two resistors when connected in series and parallel with a given battery. The provided information includes the voltage of the battery and the current through the circuit in each configuration.

1. **Series Configuration**:
- Voltage (V) = 12 V
- Current (I) = 0.36 A

2. **Parallel Configuration**:
- Voltage (V) = 12 V
- Current (I) = 1.60 A

Use Ohm's Law (V = IR) to calculate the resistances systematically, considering the series and parallel arrangements.

### Graphs/Diagrams
There are no graphs or diagrams included in this problem.

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