Three resistors in parallel have an equivalent resistance of 5.0 2. Two of the resistors have resistances of 20 2 and 40 N. ▼ Part A What is the resistance of the third resistor? Express your answer with the appropriate units. μà ? R= Value Units Submit Provide Feedback Request Answer
Three resistors in parallel have an equivalent resistance of 5.0 2. Two of the resistors have resistances of 20 2 and 40 N. ▼ Part A What is the resistance of the third resistor? Express your answer with the appropriate units. μà ? R= Value Units Submit Provide Feedback Request Answer
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![### Question:
**Three resistors in parallel have an equivalent resistance of 5.0 Ω. Two of the resistors have resistances of 20 Ω and 40 Ω.**
#### Part A
**What is the resistance of the third resistor?**
*Express your answer with the appropriate units.*
```
R = [Value] [Units]
[Submit Button] [Request Answer]
[Provide Feedback]
```
### Explanation:
In this problem involving resistors in parallel, you are given two resistor values and the equivalent resistance of the circuit. You need to determine the resistance of the third resistor.
#### Steps to Solve:
1. **Identify the Information Given:**
- Equivalent resistance \( R_{eq} = 5.0 \, \Omega \)
- Resistance of the first resistor \( R_1 = 20 \, \Omega \)
- Resistance of the second resistor \( R_2 = 40 \, \Omega \)
2. **Apply the Formula for Parallel Resistors:**
\[
\frac{1}{R_{eq}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3}
\]
3. **Input Known Values:**
\[
\frac{1}{5.0} = \frac{1}{20} + \frac{1}{40} + \frac{1}{R_3}
\]
4. **Calculate \( \frac{1}{R_3} \):**
- Calculate the sum on the right-hand side for the known resistors:
\[
\frac{1}{20} + \frac{1}{40} = \frac{2 + 1}{40} = \frac{3}{40}
\]
- Substitute and solve for \( \frac{1}{R_3} \):
\[
\frac{1}{5.0} = \frac{3}{40} + \frac{1}{R_3}
\]
\[
\frac{1}{R_3} = \frac{1}{5.0} - \frac{3}{40}
\]
5. **Simplify the Calculation:**
- Find a common denominator and perform the subtraction:
\[
\frac{1}{5.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffea86598-763f-4f77-8aa1-6d0907d2b5d9%2F67278e5a-ae86-4ead-9445-67b08180c246%2Faa2ifoq_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Question:
**Three resistors in parallel have an equivalent resistance of 5.0 Ω. Two of the resistors have resistances of 20 Ω and 40 Ω.**
#### Part A
**What is the resistance of the third resistor?**
*Express your answer with the appropriate units.*
```
R = [Value] [Units]
[Submit Button] [Request Answer]
[Provide Feedback]
```
### Explanation:
In this problem involving resistors in parallel, you are given two resistor values and the equivalent resistance of the circuit. You need to determine the resistance of the third resistor.
#### Steps to Solve:
1. **Identify the Information Given:**
- Equivalent resistance \( R_{eq} = 5.0 \, \Omega \)
- Resistance of the first resistor \( R_1 = 20 \, \Omega \)
- Resistance of the second resistor \( R_2 = 40 \, \Omega \)
2. **Apply the Formula for Parallel Resistors:**
\[
\frac{1}{R_{eq}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3}
\]
3. **Input Known Values:**
\[
\frac{1}{5.0} = \frac{1}{20} + \frac{1}{40} + \frac{1}{R_3}
\]
4. **Calculate \( \frac{1}{R_3} \):**
- Calculate the sum on the right-hand side for the known resistors:
\[
\frac{1}{20} + \frac{1}{40} = \frac{2 + 1}{40} = \frac{3}{40}
\]
- Substitute and solve for \( \frac{1}{R_3} \):
\[
\frac{1}{5.0} = \frac{3}{40} + \frac{1}{R_3}
\]
\[
\frac{1}{R_3} = \frac{1}{5.0} - \frac{3}{40}
\]
5. **Simplify the Calculation:**
- Find a common denominator and perform the subtraction:
\[
\frac{1}{5.
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