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When the imaginary part is zero (at o= wo) we are left with L2 1 1 hence gm L2 -w,LL, + wLL,R R @LC 1 Now o thus substituting this expression for wo, we find (L1 +L2)C' 1 L+L2 L, L LRG 1 -1 Em 2 R. RG (4+ L,)c4C L The condition for oscillation is therefore g, LRG

When the imaginary part is zero (at o= wo) we are left with L2 1 1 hence gm L2 -w,LL, + wLL,R R @LC 1 Now o thus substituting this expression for wo, we find (L1 +L2)C' 1 L+L2 L, L LRG 1 -1 Em 2 R. RG (4+ L,)c4C L The condition for oscillation is therefore g, LRG

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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When the imaginary part is zero (at o= wo) we are left with L2 +7'7?0- hence gm 1 1 L2 wLL,R R oLC -w,L,L, + 1 Now o thus substituting this expression for wo, we find (L1 +L2)C' 1 L+L2 L L LRG 1 -1 Em R. RG (4+ L,)c4C The condition for oscillation is therefore g LRG
Transcribed Image Text:When the imaginary part is zero (at o= wo) we are left with L2 +7'7?0- hence gm 1 1 L2 wLL,R R oLC -w,L,L, + 1 Now o thus substituting this expression for wo, we find (L1 +L2)C' 1 L+L2 L L LRG 1 -1 Em R. RG (4+ L,)c4C The condition for oscillation is therefore g LRG
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