When the following gas reaction reaches equilibrium, at a certain temperature, the moles fractions four reactive species satisfy the following relation (we will use "y" for mole fractions since all of thes reagents and products are gases): CO+H20 CO2+H2 K= [yCO2][yH2] [yCo][YH20] Where K= 1. Assume that the feed introduced to the reactor is 2 mol of CO and 4 mol of H20 only. Al: assume that the reaction reaches equilibrium. a) Calculate the equilibrium composition, for this you need to calculate the mole fraction for all reactants and products. Answer: yCo2 = 2/9 yH2 yCo = 1/9 YH2O = 4/9| = 2/9
When the following gas reaction reaches equilibrium, at a certain temperature, the moles fractions four reactive species satisfy the following relation (we will use "y" for mole fractions since all of thes reagents and products are gases): CO+H20 CO2+H2 K= [yCO2][yH2] [yCo][YH20] Where K= 1. Assume that the feed introduced to the reactor is 2 mol of CO and 4 mol of H20 only. Al: assume that the reaction reaches equilibrium. a) Calculate the equilibrium composition, for this you need to calculate the mole fraction for all reactants and products. Answer: yCo2 = 2/9 yH2 yCo = 1/9 YH2O = 4/9| = 2/9
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![When the following gas reaction reaches equilibrium, at a certain temperature, the moles fractions of the
four reactive species satisfy the following relation (we will use "y" for mole fractions since all of these
reagents and products are gases):
CO+H20 >
CO2+H2
[yCO2][yH2]
K=
[yC0][YH20]
Where K= 1. Assume that the feed introduced to the reactor is 2 mol of CO and 4 mol of H20 only. Also
assume that the reaction reaches equilibrium.
need to calculate the mole fraction for all
a) Calculate the equilibrium composition, for this
reactants and products.
Answer: yCo2 = 2/9
= 2/9
yH2
УСо - 1/9
YH2O = 4/9|](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F36c3d98d-d4ef-4c5a-844b-ca69416c18f2%2F3b41bf5f-8a19-48e0-93a8-273458d7686a%2Fqr78h4k_processed.jpeg&w=3840&q=75)
Transcribed Image Text:When the following gas reaction reaches equilibrium, at a certain temperature, the moles fractions of the
four reactive species satisfy the following relation (we will use "y" for mole fractions since all of these
reagents and products are gases):
CO+H20 >
CO2+H2
[yCO2][yH2]
K=
[yC0][YH20]
Where K= 1. Assume that the feed introduced to the reactor is 2 mol of CO and 4 mol of H20 only. Also
assume that the reaction reaches equilibrium.
need to calculate the mole fraction for all
a) Calculate the equilibrium composition, for this
reactants and products.
Answer: yCo2 = 2/9
= 2/9
yH2
УСо - 1/9
YH2O = 4/9|
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