When the following equation is balanced correctly, what is the coefficient in front of Ba(NO3)2? Ba(NO3)2 + Na3PO4 → - Ba3(PO4)2 + NaNO3 d. 6 a. 1 b. 2 c. 3 e. 12
When the following equation is balanced correctly, what is the coefficient in front of Ba(NO3)2? Ba(NO3)2 + Na3PO4 → - Ba3(PO4)2 + NaNO3 d. 6 a. 1 b. 2 c. 3 e. 12
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
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![### Question 26: Balancing Chemical Equations
**Question:**
When the following equation is balanced correctly, what is the coefficient in front of Ba(NO₃)₂?
\[ \text{Ba(NO}_3\text{)}_2 + \text{Na}_3\text{PO}_4 \rightarrow \text{Ba}_3(\text{PO}_4)_2 + \text{NaNO}_3 \]
- a. 1
- b. 2
- c. 3
- d. 6
- e. 12
**Explanation:**
To balance this chemical equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation.
The given unbalanced equation is:
\[ \text{Ba(NO}_3\text{)}_2 + \text{Na}_3\text{PO}_4 \rightarrow \text{Ba}_3(\text{PO}_4)_2 + \text{NaNO}_3 \]
First, let's list the number of each atom on both sides:
Reactants:
- Ba: 1
- N: 2
- O: 6 (from \( \text{Ba(NO}_3\text{)}_2 \))
- Na: 3
- P: 1
- O: 4 (from \( \text{Na}_3\text{PO}_4 \))
Products:
- Ba: 3
- P: 2
- O: 8 (from \( \text{Ba}_3(\text{PO}_4)_2 \))
- Na: 1
- N: 1
- O: 3 (from \( \text{NaNO}_3 \))
Next, balance the equation by adjusting coefficients so the number of each type of atom is equal on both sides.
Balanced equation steps:
Step 1: Balance the barium (Ba) atoms by placing a coefficient of 3 in front of Ba(NO₃)₂:
\[ 3\text{Ba(NO}_3\text{)}_2 + \text{Na}_3\text{PO}_4 \rightarrow \text{Ba}_3(\text{PO}_4)_2 + \text{NaNO}_3 \]
Step 2: Balance the sodium (Na) atoms by placing a coefficient of 3 in front of NaNO₃:](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F066bb5df-9069-4300-b122-0f92c568ce58%2F4e315314-336e-440a-9254-dc6c970d2085%2Fhvwjt3_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Question 26: Balancing Chemical Equations
**Question:**
When the following equation is balanced correctly, what is the coefficient in front of Ba(NO₃)₂?
\[ \text{Ba(NO}_3\text{)}_2 + \text{Na}_3\text{PO}_4 \rightarrow \text{Ba}_3(\text{PO}_4)_2 + \text{NaNO}_3 \]
- a. 1
- b. 2
- c. 3
- d. 6
- e. 12
**Explanation:**
To balance this chemical equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation.
The given unbalanced equation is:
\[ \text{Ba(NO}_3\text{)}_2 + \text{Na}_3\text{PO}_4 \rightarrow \text{Ba}_3(\text{PO}_4)_2 + \text{NaNO}_3 \]
First, let's list the number of each atom on both sides:
Reactants:
- Ba: 1
- N: 2
- O: 6 (from \( \text{Ba(NO}_3\text{)}_2 \))
- Na: 3
- P: 1
- O: 4 (from \( \text{Na}_3\text{PO}_4 \))
Products:
- Ba: 3
- P: 2
- O: 8 (from \( \text{Ba}_3(\text{PO}_4)_2 \))
- Na: 1
- N: 1
- O: 3 (from \( \text{NaNO}_3 \))
Next, balance the equation by adjusting coefficients so the number of each type of atom is equal on both sides.
Balanced equation steps:
Step 1: Balance the barium (Ba) atoms by placing a coefficient of 3 in front of Ba(NO₃)₂:
\[ 3\text{Ba(NO}_3\text{)}_2 + \text{Na}_3\text{PO}_4 \rightarrow \text{Ba}_3(\text{PO}_4)_2 + \text{NaNO}_3 \]
Step 2: Balance the sodium (Na) atoms by placing a coefficient of 3 in front of NaNO₃:
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