When the effect of aerodynamic drag is included, the y-acceleration of a baseball moving vertically upward is a = -g- kv², while the acceleration when the ball is moving downward is ad=-g+kv², where k is a positive constant and v is the speed in meters per second. If the ball is thrown upward with an initial speed of 30 m/s, determine the time t, from ground to apex and the time to from apex to ground. Take k to be 0.007 m¹ and assume that g is constant. au=-g-kv² y Answers: tu= i td = i 30 m/s ad=-g+kv² S S h
When the effect of aerodynamic drag is included, the y-acceleration of a baseball moving vertically upward is a = -g- kv², while the acceleration when the ball is moving downward is ad=-g+kv², where k is a positive constant and v is the speed in meters per second. If the ball is thrown upward with an initial speed of 30 m/s, determine the time t, from ground to apex and the time to from apex to ground. Take k to be 0.007 m¹ and assume that g is constant. au=-g-kv² y Answers: tu= i td = i 30 m/s ad=-g+kv² S S h
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![When the effect of aerodynamic drag is included, the y-acceleration of a baseball moving vertically upward is a = -g- kv², while the
acceleration when the ball is moving downward is ad=-g+kv², where k is a positive constant and v is the speed in meters per second. If
the ball is thrown upward with an initial speed of 30 m/s, determine the time tu from ground to apex and the time to from apex to
ground. Take k to be 0.007 m¹ and assume that g is constant.
au=-g-kv²
y
Answers:
tu=
t₁ =
i
i
30 m/s
ad=-g+kv²
S
S
h](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F68c8d59a-da57-447f-9f0c-adb1654ae0a5%2Ffc52336a-b543-4ee2-89df-af9f177c9bc7%2Fm1h7uif_processed.jpeg&w=3840&q=75)
Transcribed Image Text:When the effect of aerodynamic drag is included, the y-acceleration of a baseball moving vertically upward is a = -g- kv², while the
acceleration when the ball is moving downward is ad=-g+kv², where k is a positive constant and v is the speed in meters per second. If
the ball is thrown upward with an initial speed of 30 m/s, determine the time tu from ground to apex and the time to from apex to
ground. Take k to be 0.007 m¹ and assume that g is constant.
au=-g-kv²
y
Answers:
tu=
t₁ =
i
i
30 m/s
ad=-g+kv²
S
S
h
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