When the current in a long, straight, air-filled solenoid is changing at the rate of 1500 A/s, the voltage across the solenoid is 0.600 V. The solenoid has 1200 tuns and uniform cross-sectional area 35.0 mm2. Assume that the magnetic field is uniform inside the solenoid and zero outside, so the inductance formula L = o AN? /l for a solenoid with N tums, uniform cross-sectional area A, and length I, applies. Part A What is the magnitude B of the magnetic field in the interior of the solenoid when the current in the solenoid is 3.00 A? Express your answer with the approppriate units. ? B = Value Units

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**Educational Content: Magnetic Field in a Solenoid**

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**Theoretical Background:**

When the current in a long, straight, air-filled solenoid is changing at the rate of 1500 A/s, the voltage across the solenoid is 0.600 V. The solenoid has 1200 turns and a uniform cross-sectional area of 35.0 mm². Assume that the magnetic field is uniform inside the solenoid and zero outside. Thus, the inductance formula 

\[ L = \frac{{\mu_0 AN^2}}{l} \]

for a solenoid with \( N \) turns, uniform cross-sectional area \( A \), and length \( l \) applies.

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**Problem Statement (Part A):**

What is the magnitude \( B \) of the magnetic field in the interior of the solenoid when the current in the solenoid is 3.00 A?

**Instruction:**

Express your answer with the appropriate units.

**Input Field:**

\[ B = \, \text{(Enter Value)} \, \text{(Enter Units)} \]

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This problem requires understanding of electromagnetic induction and the properties of solenoids, applying principles such as the inductance of a solenoid and calculating the magnetic field generated within it.
Transcribed Image Text:**Educational Content: Magnetic Field in a Solenoid** --- **Theoretical Background:** When the current in a long, straight, air-filled solenoid is changing at the rate of 1500 A/s, the voltage across the solenoid is 0.600 V. The solenoid has 1200 turns and a uniform cross-sectional area of 35.0 mm². Assume that the magnetic field is uniform inside the solenoid and zero outside. Thus, the inductance formula \[ L = \frac{{\mu_0 AN^2}}{l} \] for a solenoid with \( N \) turns, uniform cross-sectional area \( A \), and length \( l \) applies. --- **Problem Statement (Part A):** What is the magnitude \( B \) of the magnetic field in the interior of the solenoid when the current in the solenoid is 3.00 A? **Instruction:** Express your answer with the appropriate units. **Input Field:** \[ B = \, \text{(Enter Value)} \, \text{(Enter Units)} \] --- This problem requires understanding of electromagnetic induction and the properties of solenoids, applying principles such as the inductance of a solenoid and calculating the magnetic field generated within it.
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