When reducing 3-SAT to the Clique problem, edges are added between every literal in the graph G, except (select all that apply): Between literals in the same clause Between common literals such as A from one clause and A from another Between conflicting literals such as A and !A The first and last literals in the problem When adding such an edge would give the node a degree greater than 3
![Question 3
When reducing 3-SAT to the Clique problem, edges are added between every literal in the graph G, except (select all that apply):
Between literals in the same clause
Between common literals such as A from one clause and A from another
Between conflicting literals such as A and !A
The first and last literals in the problem
When adding such an edge would give the node a degree greater than 3](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F04d42f7e-0130-4413-8fc1-c7437b10f286%2F2803a086-8ce4-4d67-8bea-33e28f926dba%2Fv0o8pzv_processed.png&w=3840&q=75)
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In reducing 3-SAT to the clique problem, we create a graph G with one node for each variable and its negation in each clause, and add edges between the nodes to represent the constraint that both variables cannot be true.
The 3-SAT problem is a classic NP-complete problem in computer science that asks whether a Boolean formula in conjunctive normal form (CNF) can be satisfied by assigning truth values to its variables.
The clique problem is another NP-complete problem that asks whether a graph contains a complete subgraph of a given size.
To reduce 3-SAT to a clique problem, we first create a graph where nodes represent literals in the 3-SAT problem, and then add edges that represent clauses. The resulting graph can then be converted to a crank problem, and the answer to the 3-SAT problem can be found by solving the corresponding crank problem.
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