so seq, returned by a call to DFSValid (G), is a valid ordering of G (if one exists)? Line= integer ? At what even line number should we add if w not in seq then fail so DFS fails if the graph has no valid ordering? Note: multiple line numbers are possible locations. Enter the first possible line number. Line= integer ?
so seq, returned by a call to DFSValid (G), is a valid ordering of G (if one exists)? Line= integer ? At what even line number should we add if w not in seq then fail so DFS fails if the graph has no valid ordering? Note: multiple line numbers are possible locations. Enter the first possible line number. Line= integer ?
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Transcribed Image Text:Part 2
We want to find a valid ordering for a graph or determine that no such ordering exists. We'll use
depth-first search to do it. Notice that the pseudocode we've given you has only odd line
numbers. We'll adapt DFS to our purpose by adding two even numbered lines. Note: This is DFS in
a directed graph. The edge (v, w) is directed from v to w.
19 DFSValid (G) {
21
23
25
27
29
31
33
35
37 }
unmark all vertices.
unmark all edges
for each vertex v {
51
53
55
57
59}
if v is unmarked {
DFS (G,V)
}
}
return seq
39 DFS (G, v) {
41
mark v
43
for each edge (v,w) {
45
if w is unmarked {
47
49
}
mark (v,w) TREE
DFS (G,w)
} else if (v,w) is unmarked {
mark (v,w) NONTREE
}
Note that seq is a global variable that is initially an empty list. At what even line number should we
add
add v to front of seq
so seq, returned by a call to DFSValid (G), is a valid ordering of G (if one exists)?
Line= integer
At what even line number should we add
if w not in seq then fail
so DFS fails if the graph has no valid ordering? Note: multiple line numbers are possible locations.
Enter the first possible line number.
Line=
integer
?
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