When originally purchased, a vehicle costing $25,380 had an estimated useful life of 8 years and an estimated salvage value of $2,900. After 4 years of straight-line depreciation, the asset's total estimated useful life was revised from 8 years to 6 years and there was no change in the estimated salvage value. The depreciation expense in year 5 equals: Multiple Choice O O O $2,810.00. $5,620.00. $2,978.00. $5,788.00. $11,240.00.

College Accounting, Chapters 1-27 (New in Accounting from Heintz and Parry)
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Author:James A. Heintz, Robert W. Parry
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Chapter18: Accounting For Long-term Assets
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### Depreciation Calculation Example

#### Scenario:
When originally purchased, a vehicle costing $25,380 had an estimated useful life of 8 years and an estimated salvage value of $2,900. After 4 years of straight-line depreciation, the asset’s total estimated useful life was revised from 8 years to 6 years and there was no change in the estimated salvage value. 

#### Question:
The depreciation expense in year 5 equals:

#### Answer Options (Multiple Choice):
1. $2,810.00.
2. $5,620.00.
3. $2,978.00.
4. $5,788.00.
5. $11,240.00. 

---

#### Explanation:
Straight-line depreciation is calculated using the formula: 

\[ \text{Annual Depreciation Expense} = \frac{\text{Cost} - \text{Salvage Value}}{\text{Useful Life}} \]

1. **Initial Calculation (Original Useful Life of 8 Years):**
   - Annual Depreciation = \( \frac{25,380 - 2,900}{8} \)
   - Annual Depreciation = \( \frac{22,480}{8} = 2,810 \).

   So, for the first 4 years:
   - Accumulated Depreciation = \( 2,810 \times 4 = 11,240 \).
   - Book Value after 4 years = Cost - Accumulated Depreciation 
   - Book Value after 4 years = \( 25,380 - 11,240 = 14,140 \).

2. **Revised Calculation (Revised Useful Life of 6 Years):**
   - Remaining Depreciable Amount = Book Value after 4 years - Salvage Value 
   - Remaining Depreciable Amount = \( 14,140 - 2,900 = 11,240 \).
   - Remaining Useful Life = 6 years - 4 years = 2 years.
   - Revised Annual Depreciation = \( \frac{11,240}{2} = 5,620 \).

Therefore, the depreciation expense in year 5 is **$5,620.00**.

---

This example demonstrates the adjustment of depreciation expense due to the revision in the estimated useful life of the asset.
Transcribed Image Text:### Depreciation Calculation Example #### Scenario: When originally purchased, a vehicle costing $25,380 had an estimated useful life of 8 years and an estimated salvage value of $2,900. After 4 years of straight-line depreciation, the asset’s total estimated useful life was revised from 8 years to 6 years and there was no change in the estimated salvage value. #### Question: The depreciation expense in year 5 equals: #### Answer Options (Multiple Choice): 1. $2,810.00. 2. $5,620.00. 3. $2,978.00. 4. $5,788.00. 5. $11,240.00. --- #### Explanation: Straight-line depreciation is calculated using the formula: \[ \text{Annual Depreciation Expense} = \frac{\text{Cost} - \text{Salvage Value}}{\text{Useful Life}} \] 1. **Initial Calculation (Original Useful Life of 8 Years):** - Annual Depreciation = \( \frac{25,380 - 2,900}{8} \) - Annual Depreciation = \( \frac{22,480}{8} = 2,810 \). So, for the first 4 years: - Accumulated Depreciation = \( 2,810 \times 4 = 11,240 \). - Book Value after 4 years = Cost - Accumulated Depreciation - Book Value after 4 years = \( 25,380 - 11,240 = 14,140 \). 2. **Revised Calculation (Revised Useful Life of 6 Years):** - Remaining Depreciable Amount = Book Value after 4 years - Salvage Value - Remaining Depreciable Amount = \( 14,140 - 2,900 = 11,240 \). - Remaining Useful Life = 6 years - 4 years = 2 years. - Revised Annual Depreciation = \( \frac{11,240}{2} = 5,620 \). Therefore, the depreciation expense in year 5 is **$5,620.00**. --- This example demonstrates the adjustment of depreciation expense due to the revision in the estimated useful life of the asset.
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