When lead (II) nitrate reacts with sodium iodide, sodium nitrate and lead (II) iodide are formed. The balanced chemical equation is: Pb(NO3)2 (aq) + 2 NaI (aq) -  PbI2 (s) + 2 NaNO3 (aq)  If, during this reaction, 23.2 grams of lead (II) nitrate is mixed with 16.8 grams of sodium iodide, Calculate the theoretical yield of lead(II) iodide (provide your answer to the appropriate number of significant figures).

General Chemistry - Standalone book (MindTap Course List)
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ISBN:9781305580343
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
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Chapter4: Chemical Reactions
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Problem 4.141QP: Lead(II) nitrate reacts with cesium sulfate in an aqueous precipitation reaction. What are the...
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. As part of the Paracetamol synthesis lab, the students also had to perform the following calculation to demonstrate their knowledge. Are you able to help them work this out?

 

When lead (II) nitrate reacts with sodium iodide, sodium nitrate and lead (II) iodide are formed.

The balanced chemical equation is:

Pb(NO3)2 (aq) + 2 NaI (aq) -  PbI2 (s) + 2 NaNO3 (aq)

 If, during this reaction, 23.2 grams of lead (II) nitrate is mixed with 16.8 grams of sodium iodide,

  1. Calculate the theoretical yield of lead(II) iodide (provide your answer to the appropriate number of significant figures).
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  1. If 19.2 grams of lead(II) iodide are actually formed in the reaction described above, what is the percent yield of this reaction? (1) (Provide your answer to the appropriate number of significant figures).
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