1. A technician carries out several trials of a reaction that produces solid antimony, Sb(s). a) What is the percentage yield in each case? Trial 1: theoretical yield = 3.33 g Sb; actual yield = 3.02 g Sb percentage yield = Trial 2: theoretical yield = 5.82 g Sb; actual yield = 4.01 g Sb percentage yield = _% Trial 3: theoretical yield = 2.05 g Sb; actual yield = 1.95 g Sb percentage yield = b) Which trial would you consider the most efficient? Explain your answer.

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1. A technician carries out several trials of a reaction that produces solid antimony, Sb(s).
a) What is the percentage yield in each case?
Trial 1: theoretical yield = 3.33 g Sb; actual yield = 3.02 g Sb
percentage yield =
Trial 2: theoretical yield = 5.82 g Sb; actual yield = 4.01 g Sb
percentage yield =
_%
Trial 3: theoretical yield = 2.05 g Sb; actual yield = 1.95 g Sb
percentage yield =
b) Which trial would you consider the most efficient? Explain your answer.
Transcribed Image Text:1. A technician carries out several trials of a reaction that produces solid antimony, Sb(s). a) What is the percentage yield in each case? Trial 1: theoretical yield = 3.33 g Sb; actual yield = 3.02 g Sb percentage yield = Trial 2: theoretical yield = 5.82 g Sb; actual yield = 4.01 g Sb percentage yield = _% Trial 3: theoretical yield = 2.05 g Sb; actual yield = 1.95 g Sb percentage yield = b) Which trial would you consider the most efficient? Explain your answer.
2. For a demonstration, a teacher dissolves 5.38 g of potassium iodide, KI, in water, and adds an excess of
lead(II) nitrate, Pb(NO,), dissolved in water, to the solution. The reaction proceeds as shown in the
chemical equation below.
Pb(NO,),(aq) + 2KI(aq) → 2KNO,(aq) + Pbl.(s)
After filtering and drying the precipitate, the teacher determines that 7.02 g of lead(II) iodide, Pbls, have
been produced.
a) What is the theoretical yield of Pbl:(s)?
b) What is the percentage yield of Pbl:(s)?
Copyright © 2014 McGraw-Hil Ryerson
978-1-25-927538-8
Chemistry 12 College Preparation Worksheet
DATE
CLASS
CHAPTER 6
WKS Topic 6.7-2
Percentage Yield
Practice Problems
WORKSHEET
3. A student heats 2.05 g of calcium carbonate, CaCO.(s) so that it decomposes according to the chemical
equation below. After the reaction, the student measures 1.38 g of solid product.
CaCO.(s) → CaO(s) + CO:(g)
a) What is the theoretical yield of solid product?
b) What is the percentage yield of solid product?
c) What is one possible explanation for the answer to part b)?
Transcribed Image Text:2. For a demonstration, a teacher dissolves 5.38 g of potassium iodide, KI, in water, and adds an excess of lead(II) nitrate, Pb(NO,), dissolved in water, to the solution. The reaction proceeds as shown in the chemical equation below. Pb(NO,),(aq) + 2KI(aq) → 2KNO,(aq) + Pbl.(s) After filtering and drying the precipitate, the teacher determines that 7.02 g of lead(II) iodide, Pbls, have been produced. a) What is the theoretical yield of Pbl:(s)? b) What is the percentage yield of Pbl:(s)? Copyright © 2014 McGraw-Hil Ryerson 978-1-25-927538-8 Chemistry 12 College Preparation Worksheet DATE CLASS CHAPTER 6 WKS Topic 6.7-2 Percentage Yield Practice Problems WORKSHEET 3. A student heats 2.05 g of calcium carbonate, CaCO.(s) so that it decomposes according to the chemical equation below. After the reaction, the student measures 1.38 g of solid product. CaCO.(s) → CaO(s) + CO:(g) a) What is the theoretical yield of solid product? b) What is the percentage yield of solid product? c) What is one possible explanation for the answer to part b)?
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