When dealing with digital signatures using DSS, it is easier to achieve selective forgery compared to existentialforgery.False, in DSS it is impossible to achieve selective forgery,False, selective forgery is more challenging because the message has to be meaningful.O True, selective forgery in DSS is easy because we can combine two message to form a third message.O True, selective forgery is always easier regardless of the scheme.Clear my choiceNext page

Actually, the answer has given below:

Answered: When dealing with digital sign forgery.…

Computer Networking: A Top-Down Approach (7th Edition)

7th Edition

ISBN:9780133594140

Author:James Kurose, Keith Ross

Publisher:James Kurose, Keith Ross

Chapter1: Computer Networks And The Internet

Section: Chapter Questions

Problem R1RQ: What is the difference between a host and an end system? List several different types of end...

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Choose between the Password Authentication Protocol (PAP) or the Challenge Handshake Authentication Protocol (CHAP) when setting up PPP authentication. If that's the case, then I'm safer from harm, right? Your response requires more background information. While setting up PPP authentication, you may use either PAP or CHAP. How come I feel safer then? Your response makes no sense out of context.
2. Recall the concept of Physically Unclonable Functions, which are an importantcomponent of hardware based security. Here is a simple scenario and simple protocol usingPUFs for authenticating a tag. In the protocol below, the Reader stores ALL possiblecombinations of Challenge-Response pairs for every tag it needs to authenticate. Duringauthentication, the Reader broadcasts the ID of the tag, and a greeting (Gn ). Every tag maysee this message, but only the one with the right ID will process the message. The right tagwith the ID in the message will then feed the greeting to its PUF and compute the responseSn. The response is then sent to the Reader. This should be clear from the Figure below. Forthe next round of authenticating the same Tag, the process repeats with a new Greeting(G n+1 ). Since the Reader has the responses, authentication is straightforward. Recall thatChallenges and Responses are typically 128 or 256 bit strings for RFIDs.From the protocol, and class, it should be…
Can authentication authentication help us reach our goals? We'll compare types' pros and cons in this section.
A secure email system is expected to provide confidentiality, sender's non-repudiation, and message integrity. Alice uses three keys to achieve this goal. The three keys are Alice's private key (KA), Bob's public key (Kg), and a randomly generated symmetric key (Ks). The encryption procedure is shown below: How can Bob 1) decrypt the data, 2) verify the message's integrity, and 3) verify the sender's non-repudiation? Describe the detailed steps (including the formulas) and show your work. KA m H(-) KA( m I am using SHA-256 KA(H(M)) Ks() KB(*) K Ks K.(m, KA(H(m)) + + KB(Ks) Internet 34
You guys use AI tool to answer. Last time I found plagiarism and AI detection in my answer. Now If you will use these things I'll surely give multiple downvotes and will report ⚠️ sure.
Two companies would like to communicate confidentially online. They also seek integrity and authenticity of the communication between each other. They require secret-key cryptography to achieve these goals. It is important for the companies that the ciphertexts exchanged are authentic and have not been altered in transit. Note that the communication between the companies comes in the form of short messages which would fit into one plaintext block of AES-128. Which of the following solutions is ideal for this scenario, where the companies share 2 secret keys, k1 which they can use for encryption and k2 which they can use for issuing and verifying MACs? Choose only 1 answer. O 1. T=HMACK2 (M) 2. C= AES-128-ENCk1(T) 3. Send C and T to the other company O 1.C-AES-128-ENCk1(M) 2. T-HMACK2(M) 3. Send C and T to the other company Any of the 3 solutions would suffice 1. C-AES-128-ENCk1(M) 2. T=HMACk2 (C) 3. Send C and T to the other company
Describe the steps of the Existential Forgery Attack against the RSA Digital Signature, as discussed in class. Then, whether or not the attacker, Oscar, is able to produce a message with the correct signature signed by Bob, state yes or no. Why?
How likely are we to succeed in achieving which of our aims if we have access to authentication resources? We'll go out the pros and cons of some different authentication strategies below.
DONT use AI, USE pencil and paper. Consider the RSA encryption scheme with a modulus n = 101 * 113, where 101 and 113 are prime numbers. You are given two potential RSA encryption exponents, e1 = 8765 and e2 = 7653. Determine which of e1 and e2 is a valid RSA encryption exponent for the given modulus n. Show all steps and Justify your answer. Note: You can use a calculator to perform the calculations involving large numbers.
Decrypt ciphertext (kx mod p = 7, ge mod p = 8). The ciphertext was created using Elgamal encryption over group Z*p with your public key (p=13, g=2, gd mod p=12) and your private key is d=6. What is the shared k value?_________ What is k-1 mod p?___________ What is the plaintext x?_________ Type each of your answers as an integer.
1. Describe the steps of the Existential Forgery Attack against RSA Digital Signature as discussed in the class. Then answer whether it is possible for the attacker, Oscar, to create a message as he wishes with the correct signature signed by Bob. Why?
In practice, we do not usually sign a document by 'encrypting' (I'm using the word loosely, here) the entire document with our private key. Instead, we calculate a digest over the entire document, and then 'encrypt' the digest. Why? Select one: a. It prevents message recovery b. The digest also provides message integrity c. It is faster d. It avoids having to raise an incredibly large number (the entire document) to a massive power

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