When chromatin is condensed, transcription cannot happen. Why not?RNA cannot access the promoter region of the geneDNA helicase cannot access the RNA strandRNA polymerase cannot access the DNA strandTranscription factors cannot access the termination region of the gene Methylation and acetylation...Actively change DNA which allows for different types of gene expressionOnly affect the construction of genes and have nothing to do with the expression of genesAre specific in which areas they affectO Occur equally throughout the body

Name: When chromatin is condensed, transcription cannot happen. Why not?RNA
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Description: When chromatin is condensed, transcription cannot happen. Why not?RNA cannot access the promoter region of the geneDNA helicase cannot access the RNA strandRNA polymerase cannot access the DNA strandTranscription factors cannot access the terminatio

The epigenetic regulation involves methylation and acetylation. By this process the gene expression…

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When chromatin is condensed, transcription cannot happen. Why not? RNA cannot access the promoter region of the gene DNA helicase cannot access the RNA strand RNA polymerase cannot access the DNA strand Transcription factors cannot access the termination region of the gene

When chromatin is condensed, transcription cannot happen. Why not? RNA cannot access the promoter region of the gene DNA helicase cannot access the RNA strand RNA polymerase cannot access the DNA strand Transcription factors cannot access the termination region of the gene

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter9: Gene Expression And Gene Regulation

Section: Chapter Questions

Problem 17QP: Given the following mRNA, write the double-stranded DNA segment that served as the template....

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Given the following mRNA, write the double-stranded DNA segment that served as the template. Indicate both the 5 and the 3 ends of both DNA strands. Also write out the tRNA anticodons and the amino acid sequence of the protein encoded by the mRNA message. DNA: mRNA: 5-CCGCAUGUUCAGUGGGCGUAAACACUGA-3 protein: tRNA:
Where does transcription take place? nucleus cytoplasm ribosome mitochondria Why must transcription occur where DNA can be found? because DNA can't leave because ribosomes are in the nucleus because DNA polymerase is found there because helicase unzips the DNA How many nucleotides equal 1 amino acid? 1 3 TRANSCRIBE this DNA sequence: TACGTTACT AUGCAAUGA ATGCAATGA AUGGATUGA TACGTTACT É O O O O O O O O
Protein synthesis is a complicated process involving DNA being transcribed to RNA, which is then translated into amino acids. Complete the DNA-to-amino acid table for three consecutive codons with the appropriate nucleotides and amino acids using a codon table. Nucleotide and amino acid options can be used multiple times or not at all. 5' to 3' DNA strand 3' to 5' DNA strand transcribed mRNA tRNA anticodon amino acid arginine cysteine leucine T A U A T G A U arginine leucine A proline T A U Answer Bank A G G с с T T A A U glutamic acid U G C G с с glutamic acid G G G с с G C arginine C G с G
Shown below is an eukaryotic gene. Assuming normal wild type RNA processing in a.cell, which of the following mature MRNAS could result in normal levels of functional synthesized proteins? Select all that apply Direction of transcription Promoter Template strand 5' Exon 4 Intron 3 Exon 3 Intron 2 Exon 2 Intron 1 Exon 1 3' 5' Coding strand Transcription start Transcription start 5' CAP-Exon1-Exon3-Exon4-AA..AAAA 5' CAP-Exon1-Exon2-Exon3-Exon4-AA...AAAA 5' CAP-Exon1-Exon2-Exon3-Exon4 Exon1-Exon2-Exon3-Exon4-.....AAAA
which of the following causes transcription to end? RNA polymerase reaches the terminator RNA polymerase binds to the promoter ribosome binds to mRNA RNA polymerase leaves promoter and goes into the reading frame ribosome reads a STOP codon
Arrange the processes involved from Transcription to Translation. RNA polymerase binds in the promoter regions Polypeptide cleavage Release of methionine and conversion to active protein Translocation Appearance of UAG codon Attachment of the mRNA to ribosome with AUG in the P site DNA rejoins Covalent bonding of AA to the tRNA Elongation of RNA transcript Binding of Rho factor Partial unwinding of DNA
Which of the following is not a control of gene transcription? The repression of a gene by the binding of a transcription factor to a silencer region Methylation of promotor sequences The stabilization of the initiation complex by transcription factors to allow RNA polymerase to begin replication The conversion of heterochromatin to euchromatin through histone demethylation The binding of an inhibitory protein to the 3' UTR
Match each of the terms in the left with the best-fitting process in the right column promoter rho initiatin codon Oric transcription initiation Origin of replication transcription initiation transcription termination translation
The diagram below shows a section of double-stranded DNA undergoing both transcription and replication. RNA polymerase (gray oval) is bound to the transcriptional template strand and moving from left to right (arrow). The resulting RNA transcript is also shown (dotted line) with limited base pairing to the template strand. The DNA sequence is specified for a portion of the double-stranded DNA. IMAGE a. Indicate whether point C is a 5' end or a 3' end of a nucleic acid. b. Indicate which strand (upper or lower) is the template for lagging strand synthesis c. Indicate the nucleotide sequence of the RNA that was transcribed from the DNA region specified by the sequence. Label the 5' and 3' ends of this sequence.
Name (Last, First): DNA An RNA polymerase attaches to the DNA and transcribes the DNA to mRNA Ribosone BIO 340 Activity # 1: DNA and the Central Dogma Complete: DNA Coding 5' ATG TGG ATT CTC AAG ATC AAT AGT 3' DNA template 3 5' Cytoplasm Nuckus Nuclear pore ARNA Use the mRNA codon sequence and the genelic Landelable in order to find the amino acid (AA) sequence of the protein. Example: if mRNA sequence is GUU then the corresponding amino acid 3-letter is Valine (Val) and the corresponding amino acid 1-letter is V. mRNA codon 5' FIRST (5') LETTER tRNA codon 3 U AA 3-letter AA 1-letter Amino acid AA - Amino acid A tRNA THE GENETIC CODE New protein being built U Pie (F) ասա UUC) ԼԱՔ Uva) Lou (L) Leu (L) val (M) Use numbers 1 to 3 to indicate the correct order of the flow of biological information. Translation Replication Transcription Hydroxyl group Deoxyribose sugar DNA's charge is negative due to following (circle the correct one): An alpha helix and a beta sheet in a protein are a type…
The RNA polymerase binds DNA template at the promoter region to initiate transcription initiates transcription using any DNA template, coding and non-coding binds at the AUG start codon to initiate transcription binds RNA template at the promoter region
In which order do the following events occur in prokaryotic transcription (from 1 = first to 4 = last)? The new RNA strand detaches from the DNA template and RNA polymerase RNA is synthesized in the 5' to 3' direction RNA polymerase reaches the termination site RNA polymerase complex binds to the promoter