when an equilibrium is disrupted (“stressed”) due to changes that a chemist imposes on the system, Le Chatelier’s Principle predicts that the equilibrium will shift in the direction that will undo as much of the change as possible. For instance, if a particular reactant compound is removed through some chemical means, then the equilibrium will shift to favor the reactants, so as to replace some of the lost compound. In this lab, you will observe the effects of stress on the tetrachlorocobaltate(II)/hexaquocobalt(II) equilibrium shown below: CoCl42-(solv) + 6 H2O(solv) Co(OH2)62+(solv) + 4 Cl-(solv) blue pink The (solv) means a solvated species. In this system, ethanol is the solvent. This means that water can not be excluded from the reaction quotient any longer, since it is now a solute in ethanol and therefore has a measurable concentration. The color of the solution provides a visual clue about the dominant cobalt species present: tetrachlorocobaltate(II) is blue and hexaquocobalt(II) is pink. Question 1: If the K values you mentioned above are different, explain whether the K value for the pink jar is larger or smaller than the blue jar, and how you know. If the K values are the same, explain how it is possible for the two jars to have different colors and still have the same K value
when an equilibrium is disrupted (“stressed”) due to changes that a chemist imposes on the system, Le Chatelier’s Principle predicts that the equilibrium will shift in the direction that will undo as much of the change as possible. For instance, if a particular reactant compound is removed through some chemical means, then the equilibrium will shift to favor the reactants, so as to replace some of the lost compound. In this lab, you will observe the effects of stress on the tetrachlorocobaltate(II)/hexaquocobalt(II) equilibrium shown below: CoCl42-(solv) + 6 H2O(solv) Co(OH2)62+(solv) + 4 Cl-(solv) blue pink The (solv) means a solvated species. In this system, ethanol is the solvent. This means that water can not be excluded from the reaction quotient any longer, since it is now a solute in ethanol and therefore has a measurable concentration. The color of the solution provides a visual clue about the dominant cobalt species present: tetrachlorocobaltate(II) is blue and hexaquocobalt(II) is pink. Question 1: If the K values you mentioned above are different, explain whether the K value for the pink jar is larger or smaller than the blue jar, and how you know. If the K values are the same, explain how it is possible for the two jars to have different colors and still have the same K value
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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when an equilibrium is disrupted (“stressed”) due to changes that a chemist imposes on the system, Le Chatelier’s Principle predicts that the equilibrium will shift in the direction that will undo as much of the change as possible. For instance, if a particular reactant compound is removed through some chemical means, then the equilibrium will shift to favor the reactants, so as to replace some of the lost compound.
In this lab, you will observe the effects of stress on the tetrachlorocobaltate(II)/hexaquocobalt(II) equilibrium shown below:
CoCl42-(solv) + 6 H2O(solv) Co(OH2)62+(solv) + 4 Cl-(solv)
blue pink
The (solv) means a solvated species. In this system, ethanol is the solvent. This means that water can not be excluded from the reaction quotient any longer, since it is now a solute in ethanol and therefore has a measurable concentration. The color of the solution provides a visual clue about the dominant cobalt species present: tetrachlorocobaltate(II) is blue and hexaquocobalt(II) is pink.
Question 1: If the K values you mentioned above are different, explain whether the K value for the pink jar is larger or smaller than the blue jar, and how you know. If the K values are the same, explain how it is possible for the two jars to have different colors and still have the same K value.
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