When a proton has a velocity v = (51+5j) x 10 m/s, it experiences a force F= -1.9 x 10-¹3 kN. In a second experiment with the same B field, the particle is moving along the+zaxis, and under these new conditions it experiences a force along the + axis. What is the magnetic field? (0+-0.2375-103 +0k)T
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Q: (3ỉ + 83) × 106 m/s, it experiences a force F = -2.7 × 10-13 k N. When a proton has a velocity v =…
A: velocity of the proton, v=3i+8j×106 m/sForce experienced, F=-2.7×10-13k^ NLet the magnetic field be…
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A: velocity, v = 6 X 107 m/s magnetic field, B = 5 X 10-5 T
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A: Charge (q) = 6.5 × 10-5 C V = 15 m/s F = 6 N
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Q: An ion with charge +4e is fired into a magnetic field of B = 2.3 mT. The velocity of the particle is…
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Q: An particle with charge -e is fired into a magnetic field B = 2.0 mT. The velocity of the particle…
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Q: a1/ A proton moving at 4.00 × 10“ m/s through a magnetic field of magnitude 1.70 T experiences a…
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Q: An electron (me = 9.11 x 10-31 kg, q = -1.602 x 1o-19 c) travels at 3.0 x 10' m/s perpendicular to a…
A: Solution:-Given thatme=9.11×10-31 kgq=-1.602×10-19 Cspeed (V)=3×107 m/sMagnetic field (B)=1.2…
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A: Given:The speed of the electron in the negative z-direction is The magnetic field in terms of the…
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- An electron moves at speed of 16.36*107 m/s perpendicular to a magnetic field. The field causes the electron to move in a circular path of radius 4*10-4 m. Find the magnetic field strength, B (in T). Mass of electron=9.1 *10-31 Kg.Please refer again to the diagram. This time we have a charge of 9.09 x 10^-6 C moving at velocity 2.16 x 10^5 m/s through a magnetic field of strength 2.53 T and an electric field of strength 9.11 x 10^5 N/C. What is the magnitude of the total force on this charge? 1.66 N 3.97 N 6.29 N 3.31 NAn electron moves up at a velocity of 9.8 x 104 m/s and has a magnetic force of 5.6 x 10-18 N pointed to the right. (me = 9.11 x 10-31 kg) a) What is the direction of the magnetic field? b) What is the strength of the magnetic field? c) What is the radius of the circle the electron makes?
- A charged particle with a charge to mass ratio of 5.7E8 C/kg travels on a circular path that is perpendicular to a magnetic field whose magnitude is 0.84 T. How much time does it take for the particle to complete one revolution?An electron moves with velocity v= (7.0i−6.0j)×10^4 m/s in a magnetic field B = (−0.80i+0.60j)T . a. Determine the x -component of the force on the electron. b. Determine the y -component of the force on the electron. c. Determine the z -component of the force on the electron.A charged particle moves into a region of uniform magnetic field, goes through half a circle, and then exits that region. The particle is either a proton or an electron (you must decide which). It spends 130 ns in the region. What is the magnitude of B? Give your answer in T. (mproton=1.672x1027 kg, melectron-9.1lx10-3! kg, e-1.602x10-19 C) OB