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Q: Problem 1.5 The beam supports a distributed load with a maximum value of 55 lb/ft at A. Part A -3…
A: The beam supports a distributed load with a maximum value of 55 lb/ft at A.Determine the resultant…
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A: To find:determine the shear and moment throughout the beam as a function of x, and draw the shear…
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A: Determine the diameter size of rods AB, BC and CA, if Yield stress = Sy = 3600 MPa and the safety…
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A: Ans Now draw the FBD of the given beam as Now the equation of parabolic load is At x=0,…
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A: Given:To find:Determine the force in members BD, CD and CE.
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A: Free body diagram is provided below
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A: Boom AB and cable CB support a crate of weight W.The force from the cable acting on the boom is…
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Q: 5.26 Find the forces in members AB, BH, BC, and DF of the truss shown in Figure P5.26. C 4 kips B D…
A: The length of members BH from similar triangle conceptFrom concept of Similar triangle :Determining…
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A: F= 15 lb
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A: w = 650 N/m
Q: long link AC is rotating at 10 rad/sec CW. the 9 inch link BD. Points C and D are 8 in
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- Springs OA and OB are originally unstretched in a vertical position. Find the horizontal force, F, when the springs are held in the position as shown, given: k = 550 lb/ft, L1 = 0.6 ft, L2 = 1.3 ft5. The figure below represents the anatomy of the lower limb when balanced on your toes and the body weight acts through the tibia. The Achilles Tendon makes an angle (0) of 8° with the vertical and for this foot x1 is 6.2 cm and x2 is 12.3 cm. Calf Muscle Tibia Achilles Tendon Calculate the tension (T) in the Achilles Tendon if a 70 kg man stands on the toes of both feet. Using the values in this example what is the mechanical advantage for this lever and describe what that means in terms of the efficiency of the lever.The following forces are acting on the bracket below (a free-body diagram of the bracket is shown), that is hinged at point 1 (bottom left point). The bracket is in equilibrium (not accelerating). The force at point 2 must act horizontally, but can act to the right or left. I drew the force acting at point 2 (the middle point) pushing the bracket to the right. For the given forces, did I draw the force acting on the bracket in the correct direction? F2 F1x 10 Ibf Yes No Can't be determined based on the given information
- The figure on the left, below, shows a non-uniform bent rod with a mass of 5 kg. Your job is to determine the location of the center of gravity of this rod. You design an experiment: you connect a pin and cable to the rod such that it safely stays in static equilibrium under a force P that you apply. Then, you apply forces between 0-100 N, and measure the tension force on the cable using a cable tension meter. The results of your experiment are shown in the figure, on the right. Using this experiment, calculate (approximately) the horizontal distance (x in the figure) between point A and the center of gravity G of the bent rod. B C O I 20 cm 20 cm 60° D 50 cm Tension measurement [N] 60 50 40 30 20 -10 0 10 real data estimated fit 20 30 40 ܐܐܝ 50 P[N] 60 70 80 90 100The figure shows the Russel fracture traction device and a mechanical model of the leg. The leg is held in balance in the position indicated by the two weights attached to the two cables. The combined weight of the leg and cast is W=180 N. The horizontal distance between points A and B where the cables are attached to the leg is L=100 cm and the vertical distance is d=5 cm. Point C is the center of gravity of the cast and leg at three quarters of the L measured from point A (3L/4= 75 cm). The angle that cable 2 makes with the horizontal is measured as β=30°. Accordingly, in order for the leg to remain in balance in the shown position; a) Find the tensile force T1 in cable 1. (Write your result in N) Answerb) Find the tensile force T2 in cable 2. (Write your result in N) Answerc) Find the angle α of cable 1 with the horizontal. ResponseThe figure shows the Russel fracture traction device and a mechanical model of the leg. The leg is held in balance in the position indicated by the two weights attached to the two cables. The combined weight of the leg and the cast is W=210 N. The horizontal distance between points A and B where the cables are attached to the leg is L=100 cm and the vertical distance is d=6 cm. Point C is the center of gravity of the cast and leg at three quarters of the L measured from point A (3L/4= 75 cm). The angle that cable 2 makes with the horizontal is measured as β=33°. Accordingly, in order for the leg to remain in balance in the shown position; a) Find the tensile force T1 in cable 1. (Write your result in N) b) Find the tensile force T2 in cable 2. (Write your result in N) c) Find the angle α of cable 1 with the horizontal.
- Two forces act on a massless block. If the force FA is known, what must the magnitude of F3 be in order to keep the block from rotating about point P. B A. FB = 3/5 FA B. FB = 3/4 FA C. FB = FA D. FB = 4/3 FA E. FB = 5/3 FA F P 4 m FB 3 mHer foot pivots as a single structure about a single pivot in her ankle. When she stands on tiptoe, her foot pivots about her ankle. As shown in the foot diagram and the free-body diagram below, the forces on one foot are an upward force on her toes from the floor, a downward force on her ankle from the lower leg bone (called the Tibia), and an upward force on the heel of her foot from her Achilles Tendon. Suppose a 61.3 kg woman stands on one foot, on tiptoe, with the sole of her foot making a 25.0 degree angle with the floor, and with the distances are as shown in the figure.Torque Problem The diagram below shows the lower leg being held in a stationary. The torque acting to turn the leg in a clockwise direction is being generated by the weight of the leg and the weight of a barbel attached to the ankle. Using the information provided calculate the magnitude of the quadriceps force. LOWER LEG IN ANGULAR EQUILIBRIUM 15° Quadriceps muscle force 0.05m 0.14 m 50° 0.30m 90 Newtons 120 Newtons Show your calculations step by step here. Includes diagrams and short comments to explain your approach to solving the problem.